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I am Lyosha [343]
3 years ago
6

What type of arc lies between the two sides of a central angle and measures less than 180?

Mathematics
1 answer:
Tanzania [10]3 years ago
8 0

Answer:

minor arc

Step-by-step explanation:

apex

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Can someone explain please​
blondinia [14]

Answer:

\large\boxed{B.\ \dfrac{7}{4}}

Step-by-step explanation:

\dfrac{\Delta y}{\Delta x}=\dfrac{14}{8}=\dfrac{14:2}{8:2}=\dfrac{7}{4}

3 0
3 years ago
Christine received a $70 gift card for a coffee store. She used it in buying some coffee that cost $7.52 per pound. After buying
Sonbull [250]

Answer:

3

Step-by-step explanation:

take 70 and subtract the amount left, which is $22.56 divide that by 7.52 and you get your answer of 3

5 0
3 years ago
The dot plots below show the test scores of seventh- and eighth-grade students: Dot plot for Grade 7 shows 6 dots on score 50, 4
sergeinik [125]
The answer for this question is Grade 7 I believe.
3 0
2 years ago
Read 2 more answers
Solve 11 ≤ w + 3.4 i dont know the answer please help me
shepuryov [24]

Answer:

7.6 ≤w

Step-by-step explanation:

Hey there!

In order to solve this inequality, you need to simplify the inequality like the following:

Subtract 3.4 from both sides

7.6 ≤w

This means that w is greater than or equal to 7.6

6 0
2 years ago
The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers
stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

(c) Confidence Interval for male expenditure is ($106.40, $136.40)

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

(c) Male

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0
3 years ago
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