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Mkey [24]
3 years ago
9

On a coordinate plane, a solid straight line has a positive slope and goes through (negative 4, 0) and (0, 2). Everything to the

right of the line is shaded. Which linear inequality is represented by the graph? y ≤ One-halfx + 2 y ≥ One-halfx + 2 y ≤ One-thirdx + 2 y ≥ One-thirdx + 2

Mathematics
2 answers:
Paha777 [63]3 years ago
9 0

Answer:

y\le\dfrac{1}{2}x+2

Step-by-step explanation:

On a coordinate plane, a solid straight line has a positive slope and goes through (negative 4, 0) and (0, 2). This line has the equation

y-0=\dfrac{2-0}{0-(-4)}(x-(-4))\\ \\y=\dfrac{1}{2}(x+4)\\ \\y=\dfrac{1}{2}x+2

The origin belongs to the shaded region, so its coordinates must satisfy the inequality. Since

\dfrac{1}{2}\cdot 0+2=2\ge 0,

then the correct inequality is

y\le\dfrac{1}{2}x+2

zzz [600]3 years ago
4 0

Answer:

A

y ≤ \frac{1}{2}x + 2

Step-by-step explanation:

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