Answer:
No. The new height of the water is less than the height of the glass(6.33 cm<10 cm)
Step-by-step explanation:
-For the water in the glass to overflow, the volume of the inserted solid must be greater than the volume of the empty space or the ensuing height of water >height of glass.
#Volume of the golf ball:

#The volume of the water in the glass:

We then equate the two volumes to the glass' volume to determine the new height of the water:

Hence, the glass will not overflow since the new height of the water is less than the height of the glass(6.33 cm<10cm).
Answer:
r = - 
Step-by-step explanation:
The n th term of a GP is
= a₁ 
where a₁ is the first term and r the common ratio
Here a₁ = 18 and a₆ = -
, then
18
= -
( divide both sides by 18 )
= -
( take the fifth root of both sides )
r =
= - 
Answer:
C
Step-by-step explanation:
Answer:
765854sdfgh
Step-by-step explanation: