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3 years ago

60° 18 Solve for x. Round to the nearest tenth.

Mathematics

1 answer:

weeeeeb [17]3 years ago

5 0

Answer:

You need to include a picture or add more o the question because I can't solve it without the rest of the problem. All I know is 60 degrees and 18. But what is the 18?

Step-by-step explanation:

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Find one length of the square (7x-3) 3(x+1)

Svetllana [295]

Area of a square = Side × Side

Side = 7x-3

Area of the square = (7x-3) × (7x-3)

= 7x(7x-3) -3(7x-3)

= 49x^2 -21x -21x +9

=49x^2 -42x +9

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3 years ago

irakobra [83]

X = 42 - 19, so A - x = 23

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3 years ago

Read 2 more answers

Problem 10-01 NPV A project has an initial cost of $66,950, expected net cash inflows of $14,000 per year for 9 years, and a cos

svlad2 [7]

Answer:

NPV = $13,676.33

Step-by-step explanation:

First, find the present value of the cash inflows. You can solve this question using a Financial calculator;

14,000 per year is a recurring cashflow hence the PMT

PMT = 14,000

I/Y = 10%

N= 9

FV =0

then CPT PV = 80,626.33

NPV = -Initial investment + PV of future cash inflows

NPV = -66,950 + 80,626.33

NPV = $13,676.33

"NPV" button, then , then "CPT".

The answer to the NPV = $13,676.33

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3 years ago

Find the modulus of the complex number 6-2i

Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

Step-by-step explanation:

Given the number

$6-2i$

We know that

$z = x + iy$

where x and y are real and $\sqrt{-1}=i$

The modulus or absolute value of z is:

$|z|\:=\sqrt{x^2+y^2}$

Therefore, the modulus of $6-2i$ will be:

$z=6-2i$

$z=6+(-2)i$

$|z|\:=\sqrt{x^2+y^2}$

$|z|\:=\sqrt{6^2+\left(-2\right)^2}$

$=\sqrt{6^2+2^2}$

$=\sqrt{36+4}$

$=\sqrt{40}$

$=\sqrt{2^2}\sqrt{2\cdot \:5}$

$=2\sqrt{2\cdot \:5}$

$=2\sqrt{10}$

Therefore, the modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

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3 years ago

Which products are negative?

Aliun [14]

Both A and D are negative products.

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3 years ago