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slavikrds [6]
3 years ago
11

Whats the answer to 3(q-7)=27? im looking for q.

Mathematics
2 answers:
horrorfan [7]3 years ago
5 0
The answer to 3(q-7) is Q=16
VMariaS [17]3 years ago
3 0

Answer:

Step-by-step explanation:

i hope i am right q=16 is my answer my bad if it is wrong

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A projectile is fired with muzzle speed 250 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe
qaws [65]

The projectile's horizontal and vertical positions at time t are given by

x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ\,t

y=30\,\mathrm m+\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ\,t-\dfrac g2t^2

where g=9.8\dfrac{\rm m}{\mathrm s^2}. Solve y=0 for the time t it takes for the projectile to reach the ground:

30+\dfrac{250}{\sqrt2}t-4.9t^2=0\implies t\approx36.2458\,\mathrm s

In this time, the projectile will have traveled horizontally a distance of

x=\dfrac{250\frac{\rm m}{\rm s}}{\sqrt2}(36.2458\,\mathrm s)\approx6400\,\mathrm m

The projectile's horizontal and vertical velocities are given by

v_x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ

v_y=\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ-gt

At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about \sqrt{176.77^2+(-178.43)^2}\dfrac{\rm m}{\rm s}\approx250\dfrac{\rm m}{\rm s}.

7 0
3 years ago
Help for brainliest and good luck
raketka [301]

18 is the correct answer

3 0
3 years ago
Read 2 more answers
Which lines are perpendicular to the line y – 1 = (x+2)? Check all that apply.
Ilya [14]

Answer:

none of them

Step-by-step explanation:

Two lines are perpendicular when satisfy the next equation: m1*m2 = -1, where m1 and m2 are the slopes o the lines.

line 1:  

y – 1 = (x+2)

y = x + 3

slope of line 1 = 1

line 2:  

y + 2 = –3(x – 4)

y + 2 = -3*x + 12

y =  -3*x + 10

slope of line 2 = -3

m1*m2 = 1*(-3 ) = -3

They are not perpendicular

line 3:  

y − 5 = 3(x + 11)

y − 5 = 3*x + 33

y = 3*x + 38

slope of line 3 = 3

m1*m3 = 1*3 = 3

They are not perpendicular

line 4:  

y = -3x –  

slope of line 4 = -3

m1*m4 = 1*(-3 ) = -3

They are not perpendicular

line 5:  

y = x – 2

slope of line 5 = 1

m1*m5 = 1*1 = 1

They are not perpendicular

line 6:  

3x + y = 7

y = -3x + 7

slope of line 6 = -3

m1*m6 = 1*(-3 ) = -3

They are not perpendicular

5 0
3 years ago
Read 2 more answers
A recipe calls for 1 cup of ground almonds. How many ounces of ground almonds should you use for this recipe if 1 pint of ground
aleksley [76]

Answer: There are 3.36 ounces of ground almonds in 1 cup.

Step-by-step explanation:

Since we have given that

1 pint = 0.42 pounds

As we know that

1 cup = 0.5 pints

1 pound = 16 ounces

So, We need to find the number of ounces.

As 1 pint = 0.42 pounds = 0.42 × 16 = 6.72 ounces

0.5 pints is given by

6.72\times 0.5\\\\=3.36\ ounces

Hence, there are 3.36 ounces of ground almonds in 1 cup.

3 0
3 years ago
Which algebraic expression is equivalent to this expression?
Eduardwww [97]

Answer:

a

Step-by-step explanation:

9(5x)=45x

9(2)=18

4(8)=32

4(-x)=-4x

45x-4x=41x

32+18=50

41x+50

6 0
3 years ago
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