See explanation below.
Explanation:
The 'difference between roots and factors of an equation' is not a straightforward question. Let's define both to establish the link between the two..
Assume we have some function of a single variable
x
;
we'll call this
f
(
x
)
Then we can form an equation:
f
(
x
)
=
0
Then the "roots" of this equation are all the values of
x
that satisfy that equation. Remember that these values may be real and/or imaginary.
Now, up to this point we have not assumed anything about
f
x
)
. To consider factors, we now need to assume that
f
(
x
)
=
g
(
x
)
⋅
h
(
x
)
.
That is that
f
(
x
)
factorises into some functions
g
(
x
)
×
h
(
x
)
If we recall our equation:
f
(
x
)
=
0
Then we can now say that either
g
(
x
)
=
0
or
h
(
x
)
=
0
.. and thus show the link between the roots and factors of an equation.
[NB: A simple example of these general principles would be where
f
(
x
)
is a quadratic function that factorises into two linear factors.
I'm not sure how to give you solid proof, like an equation or something, but you can see that out of the four coordinates, two of them have the y-value of 4 and two of them have the y-value of 2. Also, there is 1.5 in between each x-value that is paired with the same y-value... if that makes sense. So for (0.5, 2) and (3, 2), there is 1.5 in between 0.5 and 3. I hope this helps! Sorry it's a bit of a weird answer
Answer:
-320 i guess
Step-by-step explanation:
51*-2*3-21+7=-320
Answer:
Greatest integral value of K = 3.
Step-by-step explanation:
The nature of the roots of a quadratic equation is determined by the sign of the discriminant, b^2 - 4ac. For non-real roots this is negative.
2x^2 - kx + 9 = 0
The discriminant = (-k)^2 - 4*2*2 , so:
k^2 - 16 < 0 for non-real roots.
k^2 < 16
k < √16
k < 4
So the answer is 3.
The greatest integral value is 8.
0.75^2 = 0.5625.....sq rt 0.5625 = 0.75
