No, there can not be negative amplitude because it is just the distance between the max and the midline or the minimum and the midline.
I see where you might be confused because for instance in the trig equation:
y = -3 sin (.5(x-
/2)) -1, there is a negative in front of the amplitude. However, when finding the amplitude, you take the absolute value of a.
Step-by-step explanation:
it's either 3 or 2 probably
Answer:
3/32
Step-by-step explanation:
One approach to doing this probelm is to evaluate all three functions F, G and H at x = 2:
F(2) = 2(2) - 1 = 3
G(2) = 3(2) + 2 = 8
H(2) = (2)^2 = 4
3/8
Then (F/G)(2) = (3/8), and (F/G/H) = -------- = 3/32
4
Solve for x:8 (13 - 6 x) + 6 x = 0
8 (13 - 6 x) = 104 - 48 x:
6 x + 104 - 48 x = 0
6 x - 48 x = -42 x:
-42 x + 104 = 0
Subtract 104 from both sides:
(104 - 104) - 42 x = -104
104 - 104 = 0:
-42 x = -104
Divide both sides of -42 x = -104 by -42:
(-42 x)/(-42) = -104/(-42)
(-42)/(-42) = 1:
x = -104/(-42)
The gcd of 104 and -42 is 2, so -104/(-42) = -(2×52)/(2 (-21)) = 2/2×(-52)/(-21) = (-52)/(-21):
x = (-52)/-21
Multiply numerator and denominator of (-52)/(-21) by -1:
Answer: x = 52/21
