Question

Three right triangles are drawn in the coordinate plane,

Answer 1

Answer:

Triangle A:

- smaller leg = 3

- longer leg = 10

- hypotenuse = 10.4

Traingle B:

- smaller leg = 4

- longer leg = 13

- hypotenuse = 13.6

Triangle C:

- smaller leg = 5

- longer leg = 7

- hypotenuse = 8.6

Step-by-step explanation:

Let's find the distance of the legs for the 3 right triangles.

Triangle A

The smaller leg (SL) is from (2,5) to (2,8), so the length is given by the distance in the y-axis:

$SL_{A} = 8 - 5 = 3$

Hence, the lenght of the smaller leg is 3.

The longer leg (LL) is from (-8, 8) to (2, 8), so the length is given by the distance in the x-axis:

$LL_{A} = 2 - (-8) = 10$

Then, the length of the longer leg is 10.  

Now, we can find the hypotenuse (H) by using Pitagoras:

$H_{A} = \sqrt{SL_{A}^{2} + LL_{A}^{2}} = \sqrt{3^{2} + 10^{2}} = 10.4$

Triangle B

The SL is from (3, -9) to (7, -9)

The length of the SL is:

$SL_{B} = 7 - 3 = 4$

The LL is from (7, -9) to (7, 4)

The length of the LL is:

$LL_{B} = 4 - (-9) = 13$

The hypotenuse is:

$H_{B} = \sqrt{4^{2} + 13^{2}} = 13.6$

Triangle C

The SL is from (-10, -6) to (-10, -1)

The length of the SL is:

$SL_{C} = -1 - (-6) = 5$

The LL is from (-10, -6) to (-3, -6)  

The length of the LL is:

$LL_{C} = -3 - (-10) = 7$

The hypotenuse is:

$H_{C} = \sqrt{5^{2} + 7^{2}} = 8.6$

I hope it helps you!