<span>In the question "This figure shows the procedure for constructing a" The correct answer is "bisector of an angle" (option C).
To construct an angle bisector: Draw an arc that is centered at the vertex of the angle to intersect both sides of the angle. From the point of intersection of the previous arc and the both sides of the angle, draw two more arcs to intersect at a point. The radius for the two arcs must be equal. Then draw a straight line from the point of intersection of the later set of arcs and the vertex of the angle.</span>
Answer: see below
<u>Step-by-step explanation:</u>
42) 11 < 3y + 2 < 20
<u> -2 </u> <u> -2 </u> <u> -2 </u>
9 < 3y < 18
<u> ÷3 </u> <u>÷3 </u> <u> ÷3 </u>
3 < y < 6
Graph: o----------o
3 6
44) 36 ≥ 1 - 5z > -21
<u> -1 </u> <u> -1 </u> <u> -1 </u>
35 ≥ -5z > -22
<u> ÷ -5 </u> ↓ <u> ÷ -5 </u> ↓ <u>÷ -5 </u>
7 ≤ z < 4.4
Graph: o------------ ·
4.4 7
46) 6b + 3 < 15 or 4b - 2 > 18
<u> -3 </u> <u> -3 </u> <u> +2 </u> <u>+2 </u>
6b < 12 4b > 20
<u> ÷6 </u> <u>÷6 </u> <u> ÷4 </u> <u>÷4 </u>
b < 2 or b > 5
Graph: ←--------o o---------→
2 5
48) 8d < -64 and 5d > 25
÷8 ÷8 ÷5 ÷5
d < -8 and d > 5
there is no number that is both less than - 8 and greater than 5
No Solution
Graph: (empty)
50) 15x > 30 and 18x < -36
<u> ÷15 </u> <u> ÷15 </u> <u>÷18 </u> <u>÷18 </u>
x > 2 and x < -2
there is no number that is both less than - 2 and greater than 2
No Solution
Graph: (empty)
Idk the answers on your question
82 plus 47 is 134 so angle 3 would be 46 degrees. So yes
1. To solve this problem you must apply the formula for calculate the area of a regular hexagon given the apothem, which is shown below:
A=(Perimeter x Apothem)/2
2. You have the apothem, so you can calculate the perimeter. First, you have to know the lenghts of the sides:
Tan(30°)=x/√3
x=1
Side=2x
Side=2
Perimeter=2x6
Perimeter=12
3. Then, you have that the area of the base is:
A=(Perimeter x Apothem)/2
A=12x√3/2
A=6√3
A=10.39
B=10.39 cm²
The answer is: B=10.39 cm²
