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nirvana33 [79]
4 years ago
15

P(2) = 14 and p(-3) = 0. Write one factor of p(x) and explain how you know

Mathematics
1 answer:
skad [1K]4 years ago
6 0

Answer:

Step-by-step explanation:

Given p(2) = 14 and p(-3) = 0, according to factor theorem, if a polynomial p(x) is divided by a function x+c where c is a constant, then x+c is said to be a factor of p(x) if p(-c) = 0 i.e if the remainder is zero after the division.

According to the question, it can be seen that p(-3) = 0. This means that the function x+3 is said to be factor if the remainder of the polynomial is zero when divided the polynomial because the reminder leaves zero after division where c = 3

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Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y
Yuri [45]

Let the curve C be the intersection of the cylinder  



16x^2+y^2=16



and the plane



x+y+z=1



The projection of C on to the x-y plane is the ellipse



16x^2+y^2=16



To see clearly that this is an ellipse, le us divide through by 16, to get



\frac{x^2}{1}+ \frac{y^2}{16}=1



or  



\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1,



We can write the following parametric equations,



x=cos(t), y=4sin(t)



for  



0\le t \le 2\pi



Since C lies on the plane,



x+y+z=1



it must satisfy its equation.



Let us make z the subject first,  



z=1-x-y



This implies that,



z=1-sin(t)-4cos(t)



We can now write the vector equation of C, to obtain,



r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))



The length of the curve of the intersection of the cylinder and the plane is now given by,



\int\limits^{2\pi}_0 {|r'(t)|} \, dt



But  



r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))



|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}



\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184



Therefore the length of the curve of the intersection  intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

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3 years ago
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