Probability of rolling a sum of 9 or a sum that is even from two number cubes is
11/18
Explanation:
When a dice is rolled there are different ways in which
9. can be obtained, which are (3,6) or (4,5) or (5,4) or (6,3). 4 options. As in all there are
6⋅6=36 options, probability is 4/36 or 1/9.
For getting an even number as sum, we can have (1,1) or (1.3) or (1,5) or (2,2) or (2,4) or (2,6) or (3,1) or (3,3) or (3,5) or (4,2) or (4,4) or (4,6) or (5,1) or (5,3) or (5,5) or (6,2) or (6,4) or (6,6) 18 options, probability is 18/36 or 1/2.
Note that the two events (getting 9 or even sum) are mutually exclusive, the probabilities can be just added i.e. combined probability is
1/9+1/2=2+9/18i.e. 11/18
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The diagram is missing but I'll assume that the arc BDC is:

And another arc, let's call it FGH. measures:

If those arc are equal, then this equation is true:

Substituting k into the first equation:

48/4 is 24 so you’ll need 28 1/4’s
Answer:
(3,6)
Step-by-step explanation:
-2x+3y=12
Let x = 3
-2(3) +3y = 12
-6+3y = 12
Add 6 to each side
-6+6 +3y = 12+6
3y = 18
Divide each side by 3
3y/3 = 18/3
y = 6