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3 years ago

Possible values for the area A of the rectangle shown are 12

Mathematics

1 answer:

KatRina [158]3 years ago

5 0

Answer:

idc its 12

Step-by-step explanation:

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Joe walked 4/9 mile in 4/5 of an hour what is his unit per mile

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The human resources managet at a company records the length in hours of one shift at work, X. He created the probability distrib

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3 years ago

What is the soloution to -4x+2=-14

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Answer:

x = 4

Step-by-step explanation:

subtract 2 from both sides. then -4x is equal to -16. divide by -4 which gives you 4. Hope this helped!

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Given the points A(3, 4) and B (6, 10), find the

Dvinal [7]

Answer:

P (5 , 8)

Step-by-step explanation:

P (x,y) partition A (x₁ , y₁) B (x₂ , y₂) into ratio AM:MB = a:b = 2:1 ... a=2 , b=1

x = (bx₁ + ax₂) / (a+b)

= (1 * 3 + 2 * 6) / (2 + 1)

= 15/3

= 5

y = (by₁ + ay₂) / (a+b)

= (1 * 4 + 2 * 10) / (2 + 1)

= 24/3

= 8

P (5 , 8)

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3 years ago

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

6 0

3 years ago