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Murljashka [212]
2 years ago
12

Polynomial standard form (9 + m)(-m + 9)

Mathematics
2 answers:
Flauer [41]2 years ago
6 0

Answer:

Step-by-step explanation:

(9 + m)(-m + 9) = (9 + m)(9 - m)      {(a+b)(a-b) = a²  - b²}

                       = 9² - m²

                       = 81 - m²

                       = -m² + 81

Amanda [17]2 years ago
5 0

Answer: -m^2+81

 

I used the foil method

(9+m)(-m+9)

first: 9*-m=-9m

second: 9*9=81

third: m*-m=-m^2

forth: m*9= 9m

then you do this:    -9m+81-m^2

                             +9m

                              ------------------

                                     81-m^2

then you set at the decending powers of x. which will give you: -m^2+81                      

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=\frac{(tanx+cotx)^2+(tan^2x-cot^2x)^2}{(tanx+cotx)^2}=\frac{(tanx+cotx)^2}{(tanx+cotx)^2}+\frac{(tan^2x-cot^2x)^2}{(tanx+cotx)^2}\\\\=1+\frac{(tanx-cotx)^2(tanx+cotx)^2}{(tanx+cotx)^2}=1+(tanx-cotx)^2\\\\=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\\\\=\left(\frac{sinx}{cosx}\right)^2+\left(\frac{cosx}{sinx}\right)^2-1=\frac{sin^2x}{cos^2x}+\frac{cos^2x}{sin^2x}-1=\frac{sin^4x+cos^4x}{sin^2x\ cos^2x}-1

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