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iris [78.8K]
3 years ago
8

What is the relationship between segment EB and segment FB in the construction of an angle bisector?

Mathematics
2 answers:
muminat3 years ago
7 0
They both contain the point B, also B is the vertex of angle EBF or FBE 
erik [133]3 years ago
4 0

They are both midpoints. Midpoints have to be equidistant from, in this case B, so this therefore makes them midpoints.

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C an anyone solve this 3(2b + 3)2 = 36<br> and if so what is it
Natali [406]
3(2b + 3)^2 = 36

Divide by 3 on both sides:
(2b + 3)^2 = 12

Square root both sides:
2b + 3=  \pm \sqrt{12}

Take away 3 from both sides:
2b= \pm \sqrt{12} - 3

Divide by 2 on both sides:
b=  \dfrac{ \sqrt{12} -3 }{2}  \ or \ b=  \dfrac{ -\sqrt{12} -3 }{2}

Answer:
b=  0.23 \ or \ -3.23


5 0
3 years ago
Read 2 more answers
Which of the following values are in the range of the function graphed below?
Dafna1 [17]

Answer:

A. 1

Step-by-step explanation:

I see only one red function line in the graph. this line represents the simple function y = 1, for x in the interval [-2,1].

the domain of a function defines the possible values for x, and the range of a function defined the possible values for y.

this function has only one possible value for y : 1

so, only A applies.

5 0
3 years ago
The 2.5% of people who slept the most got more sleep than how many hours of sleep
docker41 [41]
Based on lifelike statistics, I would say they got more sleep than about 8-10 hours.
6 0
2 years ago
Plz plz help me so i can get a good grade
Levart [38]

Area of the figure = 806.5 in²

Solution:

Length of the rectangle = 16 in

Breadth of the rectangle = 9 in

Area of the rectangle = length × breadth

                                    = 16 × 9

Area of the rectangle = 144 in²

Base of the triangle = 31 in

Height of the triangle = 20 in

Area of the triangle = \frac{1}{2}bh

                                 $=\frac{1}{2}\times 31\times 20

Area of the triangle = 310 in²

Parallel sides of the trapezium = 16 in and 31 in

Height of the trapezium = 35 – 20 = 15 in

Area of the trapezium = \frac{1}{2}\times \text{Sum of the parallel sides}\times \text{Height}

                                     $=\frac{1}{2}\times {(16+31)}\times{15}

                                     $=\frac{1}{2}\times {47}\times{15}

Area of the trapezium = 352.5 in²

Area of the figure = Area of rectangle + Area of triangle + Area of trapezium

                              = 144 in² + 310 in² + 352.5 in²

Area of the figure = 806.5 in²

8 0
3 years ago
If each unit cube has edges 3/4 foot long, what is the volume of the blue-outlined prism?
denpristay [2]

Has someone answered this I need the answer...do u know it??

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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