Use the table above to answer the question.
1 answer:
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Now, let's say, we add "x" lbs of the 60% gold alloy, so.. how much gold is in it? well, is just 60%, so (60/100) * x, or 0.6x.
likewise, if we use "y" lbs of the 40% alloy, how much gold is in it? well, 40% of y, or (40/100) * y, or 0.4y.
now, whatever "x" and "y" are, their sum must be 12.4 lbs.
we also know that the gold amount in each added up, must equal that of the 50% resulting alloy.
how much of the 40% alloy? well, y = 12.4 - x.
likewise, if we use "y" lbs of the 40% alloy, how much gold is in it? well, 40% of y, or (40/100) * y, or 0.4y.
now, whatever "x" and "y" are, their sum must be 12.4 lbs.
we also know that the gold amount in each added up, must equal that of the 50% resulting alloy.
how much of the 40% alloy? well, y = 12.4 - x.
Answer:
C) π/6
Step-by-step explanation:
The area under the curve from x=-π/2 to x=k is 3 times the area under the curve from x=k to x=π/2.
Graph: desmos.com/calculator/mezlen9hb4