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juin [17]
3 years ago
14

Identify like terms n 4n3 2m 6m 5n 2n?

Mathematics
1 answer:
dybincka [34]3 years ago
3 0
4n3 2m 6m 5n 2n  should be written as  {<span>4n^3, 2m, 6m, 5n, 2n}

4n^3 stands alone.  No other term has this format.
2m and 6m are like terms and can be combined into 8m.
5n and 2n are like terms and can be combined into 7n.


</span>
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PLZ HELP ILL MARK U BRAINLIEST!!!
lidiya [134]

Answer:

x=18

Step-by-step explanation:

7x-1=125

<u>  +1    +1</u>

<u>7x</u>=<u>126</u>

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3 0
2 years ago
What kinetic energy has a 4kg shootput thrown with a velocity of 12m/s
Tamiku [17]

Answer:

288J

Step-by-step explanation:

recall the formula for kinetic energy

KE = (1/2) mv²

where m is the mass (= 4kg)  and v is the velocity(=12 m/s)

hence

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7 0
3 years ago
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N76 [4]

Answer:

Henry will get $15.77 back.

Step-by-step explanation:

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7 0
2 years ago
What is the solution to the system of equations?
elixir [45]

Answer:

No solution

Step-by-step explanation:

-3x-4y-3z=-7\\2x-6y+2z=3\\5x-2y+5z=9\\\\

Lets consider the equation 2.

Here we multiply the LHS and RHS with (-1).

-3x-4y-3z=-7\\-(2x-6y+2z)=-3\\5x-2y+5z=9\\\\

Hence,

-3x-4y-3z=-7\\-2x+6y-2z=-3\\5x-2y+5z=9\\\\

When we add the equations we get,

0x+0y+0z=-10+9\\Hence,\\0=-1

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To figure out how many miles they still have to travel you subtract your original miles (2140) from how many miles they have already traveled (642).
So 2140 - 642 = 1498
They have 1498 miles to still travel.
4 0
2 years ago
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