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SIZIF [17.4K]
3 years ago
9

Alexis is making bread dough.The recipe requires 3/4 cup of flour and 1 2/5 teaspoon of salt. To maintain the ratio,how much sal

t is required when 1 cup of flour is used
Mathematics
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

16/5 teaspoons

Step-by-step explanation:

1/4 cups of flour uses 4/15 teaspoon so 4/15 x 4 is 16/5

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A sector with a radius of 15 cm has a central angle measure of 8pie/5
Citrus2011 [14]

Answer:

The area of the sector is 180\pi \ cm^2.

Step-by-step explanation:

We have,

Radius of circle is 15 cm

Central angle is \dfrac{8\pi}{5}\ \text{radian}

It is required to find the area of the sector. The formula used to find the area of sector is given by :

A=\dfrac{1}{2}r^2\theta

Plugging all the values in above formula as :

A=\dfrac{1}{2}\times 15^2\times \dfrac{8\pi}{5}\\A=180\pi \ cm^2

So, the area of the sector is 180\pi \ cm^2.

3 0
3 years ago
Garcia is modeling the equation 5x
anyanavicka [17]
A. 5 positive x tiles and 1 negative
8 0
2 years ago
This is a Doubt. Can someone tell me if it is right or wrong?
mr Goodwill [35]

Answer:

It's correct

Step-by-step explanation:

;)

3 0
2 years ago
I WILL GIVE 13 POINTS IF YOU SHOW YOUR WORK WITH THE ANSWER A clothing store purchased jeans from the manufacturer at a cost of
olasank [31]
First you need to find out how much Molly paid. So, $24 times 0.25 equals $6 off so $24 minus $6 equals $18. Molly paid $18 for the jeans. Then to find the percentage of increase you would find the difference between how much the store bought the jeans minus how much they sold them for which is $18-$6=$12 then u would do $12 divided by $6 which is 2 and then multiply by 100 to get 200%. So the store earned a 200% increase on the jeans they sold to Molly.
3 0
2 years ago
Read 2 more answers
The isotope cobalt-60 has a nuclear mass of 59.933820 u
Lesechka [4]
Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.

The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:

27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u

The actual mass of the nucleus of 60-Co is 59.933820 u.

Mass defect: 60.497220 u - 59.933820 u = 0.563400 u

The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2

(0.563400 u)*(931.5 MeV/u) = 524.807 MeV

3 0
3 years ago
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