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zubka84 [21]
3 years ago
5

Find the

Mathematics
1 answer:
Vlad [161]3 years ago
4 0

Answer:

Ending Balance = 600 * (1.05)^6

Ending Balance = 600 * 1.3400956406

Ending Balance = 804.06

Step-by-step explanation:

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Solve for y in -8×+4y=24
s344n2d4d5 [400]

Factor out the common term 4

-4(2x - y) = 24

Divide both sides by -4

2x-y= - 24/4

Simplify24/4 to 6

2x -y = -6

Subtract 2x from both sides

-y = -6 - 2x

Multiply both sides by -1

y = 6 + 2x

5 0
3 years ago
What is the value of x that makes the given equation true? ​x−3x=2(4+x)
Margarita [4]

the answer to your question is x= -2

5 0
3 years ago
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The length of a rectangle is "a" inches and the width is 3 inches more than its length. find the perimeter and the area
Alex73 [517]

Answer:

Step-by-step explanation:

Givens

Length = a

Width = a + 3

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P = 2L + 2w

Area = L * w

Solution

Perimeter

P = 2L +  2w

P = 2*a + 2(a + 3)             Remove the Brackets

p = 2a + 2a + 6                Combine

<u><em>P = 4a + 6</em></u>

Area

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<u><em>Area = a^2 + 3a</em></u>

7 0
2 years ago
The board of a large company is made up of 7 women and 9 men. 6 of them will go as a delegation to a national conference.
Burka [1]

Answer:

a) 5765760

b) 60480

c) 5705280

Step-by-step explanation:

Assuming that order is not important:

Number of women = 7

Number of men = 9

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n=\frac{16!}{(16-6)!}=16*15*14*13*12*11\\ n= 5765760

b) How many of these delegations have all men?

n_{men} = \frac{9!}{(9-6)!}=9*8*7*6*5*4  \\n_{men} = 60480

c) How many of these delegations have at least one woman?

n_{women >0}=n-n_{men}\\n_{women >0} =5765760-60480\\n_{women >0} =5705280

4 0
4 years ago
There are 60 boys in the third year, 24 of whom study chemistry. What percentage of third year boys study chemistry.
quester [9]

Answer:

40%

Step-by-step explanation:

24/60 = .4

8 0
3 years ago
Read 2 more answers
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