Answer:
The missing sides are 13 (small) and 2424 (big)
Step-by-step explanation:
The bigger triangle is bigger by 2 so multiply or divide the sides you do know by 2 to find the missing sides.
BC=12
ED= 12*2= 24
FD= 26
AC= 26/2= 13
So 65 dollars was what she paid
each camera INCLUDED a 60% mark UP so
she sold each at a 60% markup
65 dollars=100% of origonal camers
she sold them for 100+60=160% of origonal price
65 dollars=100%
percent means parts out of 100 so
160%=160/100=1.6
find 160% of 65
'of' means multiply so
1.6 times 65=104
she sold each camera at $104
Answer:
![Equation~=~\Large\boxed{2x+3=x+10}](https://tex.z-dn.net/?f=Equation~%3D~%5CLarge%5Cboxed%7B2x%2B3%3Dx%2B10%7D)
![x~=~\Large\boxed{7}](https://tex.z-dn.net/?f=x~%3D~%5CLarge%5Cboxed%7B7%7D)
![RS~=~\Large\boxed{6}](https://tex.z-dn.net/?f=RS~%3D~%5CLarge%5Cboxed%7B6%7D)
![RT~=~\Large\boxed{17}](https://tex.z-dn.net/?f=RT~%3D~%5CLarge%5Cboxed%7B17%7D)
Step-by-step explanation:
<u>Given information</u>
![RS=2x-8](https://tex.z-dn.net/?f=RS%3D2x-8)
![ST=11](https://tex.z-dn.net/?f=ST%3D11)
![RT=x+10](https://tex.z-dn.net/?f=RT%3Dx%2B10)
<u>Derived expression from the given information</u>
<em>Presumably, I think this is a combination of segments</em>
![RS+ST=RT](https://tex.z-dn.net/?f=RS%2BST%3DRT)
<u>Substitute values into the given expression</u>
![(2x-8)+(11)=(x+10)](https://tex.z-dn.net/?f=%282x-8%29%2B%2811%29%3D%28x%2B10%29)
<u>Combine like terms</u>
<em>The following is the expression</em>
![\Large\boxed{2x+3=x+10}](https://tex.z-dn.net/?f=%5CLarge%5Cboxed%7B2x%2B3%3Dx%2B10%7D)
<u>Subtract 3 on both sides</u>
![2x+3-3=x+10-3](https://tex.z-dn.net/?f=2x%2B3-3%3Dx%2B10-3)
![2x=x+7](https://tex.z-dn.net/?f=2x%3Dx%2B7)
<u>Subtract x on both sides</u>
![2x-x=x+7-x](https://tex.z-dn.net/?f=2x-x%3Dx%2B7-x)
![\Large\boxed{x=7}](https://tex.z-dn.net/?f=%5CLarge%5Cboxed%7Bx%3D7%7D)
<u>Substitute the x value into corresponding expressions to determine the final value</u>
![RS=2x-8=2(7)-8=14-8=\Large\boxed{6}](https://tex.z-dn.net/?f=RS%3D2x-8%3D2%287%29-8%3D14-8%3D%5CLarge%5Cboxed%7B6%7D)
![RT=x+10=(7)+10=\Large\boxed{17}](https://tex.z-dn.net/?f=RT%3Dx%2B10%3D%287%29%2B10%3D%5CLarge%5Cboxed%7B17%7D)
Hope this helps!! :)
Please let me know if you have any questions
Answer:
We know length of one quarter of a circle = 2πr/4 = πr/2
So here we can make the equation for to find thr value of radius r
length of one quarter given = 25 cm
so πr/2 = 25 cm
=> πr = 50 cm
=> r = 50/π cm
So the entire circumference of circle =
2πr
= 2 π 50/π cm
= 100π/π cm (ans)
Here we dont substitute the value of π due to represent the answer in terms of pi.
Hope it helps you