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Illusion [34]
3 years ago
5

If the Alpha company is 79% staffed and the Beta company is only 62% staffed, what is the relative change of staffing from the A

lpha company to the Beta company?
Mathematics
1 answer:
sweet [91]3 years ago
5 0

Answer:

27.41%

Step-by-step explanation:

Data provided in the question

The staffed of Alpha company = 79%

The staffed of Beta company = 62%

Based on the above information, the relative change of staffing from Alpha to beta company is

As we know that

\bold {\ Relative \ change = \frac{\alpha- \beta }{\beta }}

= \frac{(79 -62)}{62} \% \\\\= \frac{17}{62} \times 100\\\\=0.2741 \times 100\\\\=27.41\ \%

By applying the above formula we can get the relative change and the same is to be applied so that the correct percentage could come

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Answer:

a. y = -x² + 2x - 8

b. y = \frac{1}{x-2}

c. y = x³+ 3

Step-by-step explanation:

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Find the slope of the line containing the points (1, 2) and (6, 12).
Sholpan [36]

Answer:6

Step-by-step explanation:

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2 years ago
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Which of the following equations is paralllel to the line y+3x+1 and passes through the point (6,-3)
RideAnS [48]

Answer:

y=3x-21

Step-by-step explanation:

a line is parallel if the slopes of the lines are the same

so that means that out line should look something like this

y=3x+b

then, we use our point given to find b

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the equation of out line is y=3x-21

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3 years ago
How would I get the two equations into point intercept form?
prisoha [69]
Identify the slope, m. This can be done by calculating the slope between two known points of the line using the slope formula.
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5 0
3 years ago
(a) A lamp has two bulbs, each of a type with average lifetime 1400 hours. Assuming that we can model the probability of failure
Temka [501]

Answer:

For first lamp ; The resultant probability is 0.703

For both lamps; The resultant probability is 0.3614

Step-by-step explanation:

Let X be the lifetime hours of two bulbs

X∼exp(1/1400)

f(x)=1/1400e−1/1400x

P(X<x)=1−e−1/1400x

X∼exp⁡(1/1400)

f(x)=1/1400 e−1/1400x

P(X<x)=1−e−1/1400x

The probability that both of the lamp bulbs fail within 1700 hours is calculated below,

P(X≤1700)=1−e−1/1400×1700

=1−e−1.21=0.703

The resultant probability is 0.703

Let Y be a lifetime of another lamp two bulbs

Then the Z = X + Y will follow gamma distribution that is,

X+Y=Z∼gamma(2,1/1400)

2λZ∼

X+Y=Z∼gamma(2,1/1400)

2λZ∼χ2α2

The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,

P(Z≤1700)=P(1/700Z≤1.67)=

P(χ24≤1.67)=0.3614

The resultant probability is 0.3614

8 0
2 years ago
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