The speed of wind and speed of plane in still air are 23 and 135
km/h respectively.
<u>Step-by-step explanation:</u>
Let the speed of wind and speed of plane in still air are w and p km/h respectively.
The effective speed on onward journey was
................(1)
The effective speed on return journey was
..............(2)
Adding equation (1) and equation (2) we get,
⇒ ![(p+w)+(p-w) = 158+112](https://tex.z-dn.net/?f=%28p%2Bw%29%2B%28p-w%29%20%3D%20158%2B112)
⇒ ![2p = 270](https://tex.z-dn.net/?f=2p%20%3D%20270)
⇒ ![p = 135](https://tex.z-dn.net/?f=p%20%3D%20135)
Putting value of
in
we get:
⇒ ![p+w=158](https://tex.z-dn.net/?f=p%2Bw%3D158)
⇒ ![135+w=158](https://tex.z-dn.net/?f=135%2Bw%3D158)
⇒ ![w=23](https://tex.z-dn.net/?f=w%3D23)
Therefore ,The speed of wind and speed of plane in still air are 23 and 135
km/h respectively.
The answer to angle one is 92
Answer:
18
Step-by-step explanation:
You have 25 when you are done, but you made 7, so subtract that from 27.
25-7 equals 18.
Michael bought 3.5 pounds of cheese. The number of cheese depends on how many cheese are in one pound.
Answer:
A --> 57
Step-by-step explanation:
you can find the linear pair on YH by getting 180 and subtracting it by 106 giving 74. Add 74 and 49 to get 123. The rule with triangles is that all angles inside one equal 180 so get 180 and subtract it by 123 which gets you 57.