6xy^2 - xy + 8 + 12y is a polynomial of degree 3
x²-4x-5=0
The given equation is quadratic
So we can perform prime factorisation of it.
factors of -5, that add up to give -4 are -5 and 1
therefore replacing -4x by -5x+x
x²-5x+x-5=0
performing factoring by grouping,
(x²-5x)+(x-5)=0
x(x-5)+(x-5)=0
(x+1)(x-5)=0
x+1=0 and x-5=0
Answer is x=-1 and x=5
Answer:
The probability that at least one of the children get the disease from their mother is P=0.7125.
Step-by-step explanation:
This can be modeled as a binomial random variable.
The parameter p=0.34 is the probability of a child being infected, and is constant and independent of the other events.
The parameter n=3 is the number of children (sample size).
Then, we have to calculate the probabilty that at least one of the children get the disease from their mother. That is:

The probability of exactly k children being infected can be calculated as:

Then, the easiest way to calculate this probability is using the complement: the value of the probability is 1 (or 100%) less the probability that no children gets infected.

The center of this circle is at (0, 0) because there are no identifiers in front of the x and y values. After you graph the circle, you will see that (3, -1) is on the circle.