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4 years ago

11

Overtime pay definition

1 answer:

Marizza181 [45]4 years ago

4 0

In your work field, depending on the comapny, there are a certain amount of hours you can work before going into overtime. Overtime pay is when you work over the minimum corperate set hour base line. Which if you pass that certain number, you get pay and a half. Which basically means your regular hour pay, but another half of it. So say you're making $9 and hour. If you go into overtime, you'd be making $13 an hour. But only in thos overtime hours. So if you worked say 7 hours overtime, you'd make $91 just in those 7 hours.

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Plss help!<br>Question: Find a,b and c

Roman55 [17]

Answer:

See below, please

Step-by-step explanation:

The right：

${(y + c)}^{2} - b \times (x + a) \\ = ( {y}^{2} + 2yc + {c}^{2} ) - bx - ba =$

$= {y}^{2} - bx + 2cy + {c}^{2} - ab$

The left:

$= {y}^{2} - 7x - 18y + 109$

So, after comparing the right side and the left side of this equation, we know

1)

$b = 7$

2)

$2c = - 18 \\ so \\ c = - 9$

3)

${c}^{2} - ab = 109$

So,

$a = \frac{ {c}^{2} - 109}{b} = \frac{ { (- 9)}^{2} - 109}{7} = \frac{ - 28}{7} = - 4$

6 0

3 years ago

Write to show how you make a ten.then add

storchak [24]

You can write it like this 5+5

3 0

3 years ago

For the following rectangular prism, drag and drop the steps needed to find the volume in the correct order. Then type the volum

Kamila [148]

Answer:

Volume = 100 $in^{3}$

Step-by-step explanation:

Volume, V= Bh

length = 10 inches

width = 5 inches

height = 2 inches

So that,

B = 5(10)

= 50 $in^{2}$

B = 50 $in^{2}$

Then,

V = (50)(2)

= 100

v = 100 $in^{3}$

5 0

3 years ago

The standard deviation of a sample taken from population A is 17.6 for a sample of 25.

lawyer [7]

Answer:

The standard deviation of the sample mean differences is _5.23_

Step-by-step explanation:

We have a sample of a population A and a sample of a population B.

For the sample of population A, the standard deviation $\sigma_A$ is

$\sigma_A = 17.6$

The sample size $n_A$ is:

$n_A = 25$ .

For the sample of population B, the standard deviation $\sigma_B$ is

$\sigma_B = 21.2$

The sample size $n_B$ is:

$n_B = 30$ .

Then the standard deviation for the difference of means has the following form:

$\sigma=\sqrt{\frac{\sigma_A^2}{n_A}+\frac{\sigma_B^2}{n_B}}$

Finally

$\sigma=\sqrt{\frac{17.6^2}{25}+\frac{21.2^2}{30}}\\\\\sigma= 5.23$

7 0

4 years ago

Solve using elimination.<br><br> –9x − 7y = –10<br> 9x + 8y = 5

guapka [62]

Answer:

x=4y

Step-by-step explanation:

mathpapa

7 0

3 years ago