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Wewaii [24]
3 years ago
10

Look at the middle 9 of .999. What is the value of the 9 to it's right?

Mathematics
1 answer:
Zepler [3.9K]3 years ago
3 0

Answer:

The value would be thousandths.

Step-by-step explanation:

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What is the volume of a block of ice measuring 3 meters long, 1.5 meters wide, and 2 meters high? A. 900 cu. m B. 12 cu. m C. 9
lutik1710 [3]
To find volume of a rectangular prism, you simply need to multiply length times width times height. We know from the text that our block of ice is 3 meters long, 1.5 meters wide, and 2 meters high. So all we need to do is multiply:

3 * 1.5 = 4.5

4.5 * 2 = 9

The block of ice has a volume of 9 cubic meters.
Choice C is your correct answer.
Hope that helped! =)
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What is the answer to this56÷98
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Why is math important in our daily life?
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Suppose you went to a carnival. the price in was $6, and you paid $0.50 to get on each ride. if you went to the carnival and rod
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You'd do $0.50 × 11 = $5.50 which is the total cost for the rides, and then you'd add $6 to make $11.50 which is the total amount you spent.
7 0
3 years ago
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The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm. The area of printed material on the po
grin007 [14]

Answer:

Dimensions of printed poster are

length is 32 cm

width is 48 cm


Step-by-step explanation:

Let's assume

length of printed poster is x cm

width of printed poster is y cm

now, we can find area of printed poster

so, area of printed poster is

=xy

we are given that area as 1536

so, we can set it to 1536

xy=1536

now, we can solve for y

y=\frac{1536}{x}

now, we are given

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm

so, total area of poster is

A=(8+x+8)\times (12+y+12)

A=(x+16)\times (y+24)

now, we can plug back y

A=(x+16)\times (\frac{1536}{x}+24)

now, we have to minimize A

so, we will find derivative

A'=\frac{d}{dx}\left(\left(x+16\right)\left(\frac{1536}{x}+24\right)\right)

we can use product rule

A'=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)

=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)

now, we can simplify it

A'=-\frac{24576}{x^2}+24

now, we can set it to 0

and then we can solve for x

A'=-\frac{24576}{x^2}+24=0

-\frac{24576}{x^2}x^2+24x^2=0\cdot \:x^2

-24576+24x^2=0

x=32,\:x=-32

Since, x is dimension

and dimension can never be negative

so, we will only consider positive value

x=32

now, we can solve for y

y=\frac{1536}{32}

y=48

so, dimensions of printed poster are

length is 32 cm

width is 48 cm


5 0
3 years ago
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