1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Wewaii [24]
2 years ago
10

Look at the middle 9 of .999. What is the value of the 9 to it's right?

Mathematics
1 answer:
Zepler [3.9K]2 years ago
3 0

Answer:

The value would be thousandths.

Step-by-step explanation:

You might be interested in
Help asap. Like hurry
skelet666 [1.2K]

Answer:

53.85

Step-by-step explanation:

7 0
3 years ago
Describe how you could draw a diagram for a problem about finding the total length for two strings, 15 inches long and 7 inches
Varvara68 [4.7K]
Two strings are 15 inches and 7 inches long.

You could draw a diagram that has two rulers (that are longer than 12 inches).

Draw a piece of string that is exactly 15 inches on one ruler.
Draw another piece of string on the other ruler at exactly 7 inches.

Then you can find the total length of the two strings by adding 15 and 7 inches.
15 + 7 = 22

The total length of both the strings is 22 inches. You can draw a ruler and a piece of string on it at 22 inches.
5 0
3 years ago
Does any one know how to do this. It would be such a life saver if you could help me out. Thx
Aneli [31]

Answer:

1: (3 ,- 4)

2:up (a > o)

3: -4

4: 2 units to the right

5: 4 units down

6: y = (x-2)^2-4

7:

8:

9: (5,9)

10: x=5

11: (4,7) and (6,7)

12:

Step-by-step explanation:

I'm not sure if you wanted it explained or answered , so i just answered most of them. Sorry if you wanted it explained.

3 0
2 years ago
A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin
pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.  

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph.  Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, \text{ distance } =\text{ speed }\times \text{ time }

\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}

We are given that, time taken for both are same. So \frac{40}{a-11}=\frac{70}{a+11}

\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}

8 0
3 years ago
Solve for x. 8.2x−6.2−7.2x=14 Enter your answer, as a decimal, in the box. x =
slavikrds [6]

Answer is: Solve for x by simplifying both sides of the equation, then isolating the variable.

x = 20.2

6 0
3 years ago
Other questions:
  • Triangle JKL is equilateral. One side of the triangle, JL, is a diameter of circle M. Which is true about line segments JK and K
    5·2 answers
  • If f(x)=2x-7, then find f(8)​
    15·1 answer
  • What is the decimal for 7/11
    11·1 answer
  • How much can 3 go into 1458
    14·2 answers
  • Please help need someone
    8·1 answer
  • Given f(x)=3x2−5x−2 .<br><br> What is the value of f(−23) ?
    10·1 answer
  • Find the area of a vertical cross section through the centers of the bases of a cylinder with height of 27 inches and a circumfe
    10·1 answer
  • I need help on this question please
    12·1 answer
  • The solution to a problem is an irrational number. Which statement is true about the solution?
    14·1 answer
  • Find the value of x in the equation below. 2(x - 8) = 24
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!