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netineya [11]
3 years ago
7

Whats the equation of the line that passes threw -4,4 and is parrell to the line y=1/2-4

Mathematics
1 answer:
vovangra [49]3 years ago
5 0

Answer:

y=\frac{1}{2}x+6

Step-by-step explanation:

Given:

The equation of the known line is:

y=\frac{1}{2}x-4

A point on the unknown line is (-4, 4)

Now, since the two lines are parallel, their slopes must be equal.

Now, slope of the known line is the coefficient of 'x' which is \frac{1}{2}.

Therefore, the slope of the unknown line is also m=\frac{1}{2}

Now, for a line with slope 'm' and a point on it (x_1,y_1) is given as:

y-y_1=m(x-x_1)

Here, m=\frac{1}{2}, x_1=-4,y_1=4. Therefore,

y-4=\frac{1}{2}(x-(-4))\\\\y-4=\frac{1}{2}(x+4)\\\\y-4=\frac{1}{2}x+2\\\\y=\frac{1}{2}x+2+4\\\\y=\frac{1}{2}x+6

Hence, the equation of the unknown line is y=\frac{1}{2}x+6.

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Answer:

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When it hits the ground, its height above ground will be 0. Hence, we can let <em>y</em> = 0 and solve for <em>x: </em>

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\displaystyle x=\frac{-165\pm\sqrt{31641}}{-32}=\frac{165\pm\sqrt{31641}}{32}

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