Which answer choice correctly distinguishes among the three pieces of data?
1 answer:
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Following are the python program to the given question:
from collections import defaultdict #import package
import heapq as h#import package
def primsMST(gr, st_v): # defining a method primsMST that takes two values in parameters
primalMST = defaultdict(set)#defining primalMST as a variable that calls defaultdict method
v = set([st_v])# defining a variable v that calls the set method and hold its value
e_list = [(c, st_v, to)for to, c in gr[st_v].items()]#defining variable e_list that use loop to hold value in list
h.heapify(e_list)# use package that holds heapify and holds its value
while e_list:#defining while loop that checks e_list
c, s, e = h.heappop(e_list)#holding heapop method value in c,s,and e variable
if e not in v:#defining if block checks e value is not in v
v.add(e)# use add method to add value in v
primalMST[s].add(e)#use primalMST as list that adds value in mwthod
for nxt, c in gr[e].items():#defining for loop that uses nxt, and c variable that checks value in list
if nxt not in v:#defining nxt variable that checks value is not in v
h.heappush(e_list, (c, e, nxt))#add value into the heappush method
return primalMST#return method value
connects=[['A','B',1],['B','C',4],['B','D',6],['D','E',5],['C','E',1]]#defining a list connects
my_gr=dict()#defining a variable my_gr that holds method dict() value
for el in connects:#defining a for loop that uses el to count connects list value
my_gr[el[0]]=dict()#use my_gr as list hold value in dict method
my_gr[el[1]]=dict()#use my_gr as list hold value in dict method
for el in connects:#defining another for loop that uses el to count connects list
my_gr[el[0]].update({el[1]:el[2]}) # use update method that update value in my_gr
my_gr[el[1]].update({el[0]:el[2]})# use update method that update value in my_gr
x=dict(primsMST(my_gr, list(my_gr.keys())[0]))#defining x variable that calls dict method and hold its value
a=[]#defining an empty list
for k in x:#defining a for loop that uses k to hold dict method value
for no in x[k]:#defining a loop that checks list value
a.append([k,no,my_gr[k][no]])#use a that add value in list
print(a)#print list value.
Output:
Please find the attached file.
Program Explanation:
- Import package.
- defining a method primsMST that takes "gr and st_v" as parameters.
- Inside the method, a primalMST as a variable is declared that calls "defaultdict" method.
- Use the v variable that calls the set method and hold its value.
- Defining "e_list" that uses the loop to hold value in lists, and define the heapify and holds its value.
- In the next step, it defines a while loop checks e_list, and defines variable and hold value into the method and use another if to check value and return its value.
- A list "connects" is declared that holds a value and defines a "my_gr" that holds "dict" method value and uses multiple for loop to print the calculated list value.
Learn more:
dictionary: brainly.in/question/14673591
List: brainly.in/question/25140412
Answer:
The code is mentioned below.
Explanation:
This code is written in C.
Assuming that an array of 6 by 8 is already initialized and stored in a vector
which will be called or referred in program by:
Alongwith the array the variables i j and max will be initialized as integers.
CODE:
int i,j,max;
max=0;
for(i=0;i<6;i++)
{
for(j=0;j<6;j++)
{
if(max>x[i][j])
max = x[i][j];
}
}
This code will check each and every entry of 6 by 8 array and place the largest value in max.