Ask question

Ask question

All categories

3 years ago

9

A-1 grdening supply is preparing a reprt to hand out to the customerez in pointes form only.why should the reprts writers avoid

adding hyperlinks?

Computers and Technology

2 answers:

Andreyy893 years ago

4 0

Avoid hyperlinks they can give really bad viruses

ser-zykov [4K]3 years ago

3 0

Answer:

they should avoind hyperlinks becase it is unstable

Explanation:

You might be interested in

When you select the data range for a pie chart, you should be sure to include the total cell on the worksheet?

Daniel [21]

This is not a question...

5 0

3 years ago

Which component is most likely to allow physical and virtual machines to communicate with each other?

Diano4ka-milaya [45]

A component which is most likely to allow both physical and virtual machines to communicate with each other is a: virtual switch.

<h3>What is virtualization?</h3>

Virtualization can be defined as the creation of an abstract layer over computer hardware primarily through the use of a software, in order to enable the operating system (OS), storage device, server, etc., to be used by end users over the Internet.

In Cloud computing, some of the components (features) which is not required for a successful virtualization environment include the following:

Virtual machine

Host machine

Hypervisors

In conclusion, we can infer and logically deduce that a component which is most likely to allow both physical and virtual machines to communicate with each other is a virtual switch because it enables the virtual servers and the desktops to communicate.

Read more on virtualization here: brainly.com/question/14229248

#SPJ1

Complete Question:

Which component is most likely to allow physical and virtual machines to communicate with each other?

VHD.

Virtual switch.

Hyper V.

Host OS.

8 0

1 year ago

Develop an sec (single error correction) code for a 16-bit data word. generate the code for the data word 0101000000111001. show

Kipish [7]

Answer:

code = 010100000001101000101

Explanation:

Steps:

The inequality yields $2^{k} - 1 > = M+K$ , where M = 16. Therefore,

The second step will be to arrange the data bits and check the bits. This will be as follows:

Bit position number Check bits Data Bits

21 10101

20 10100

The bits are checked up to bit position 1

Thus, the code is 010100000001101000101

3 0

3 years ago

Read 2 more answers

Write a program that can be used to assign seats for a commercial airplane. The airplane has 13 rows, with six seats in each row

d1i1m1o1n [39]

Answer:

See explaination

Explanation:

#include <iostream>

#include <string>

#include <stdio.h>

#include <cst dlib>

using namespace st d;

int main(int argc, char *argv[])

{

int airplane[13][6];

char airchar[13][6];

string ticket;

int row[2];

char seat;

//--------------------------------------------

for(int i = 0; i < 13; i++)

{

for(int j = 0; j < 6; j++)

{

airchar[i][j] = '*';

airplane[i][j] = 0;

}

}

//--------------------------------------------

for(;;)

{

cout<<"Rows 1 and 2 are first class (F C)"<<endl;

cout<<"Rows 3 through 7 are business class (B C)"<<endl;

cout<<"Rows 8 through 13 are economy class (E C)"<<endl;

cout<<endl;

cout<<"* - Available"<<endl;

cout<<"X - Occupied"<<endl;

cout<<endl;

cout<<" \t A\t B\t C\t D\t E\t F"<<endl;

cout<<"Row 1\t"<<airchar[0][0]<<"\t"<<airchar[0][1]<<"\t"

<<airchar[0][2]<<"\t"<<airchar[0][3]<<"\t"<<airchar[0][4]<<"\t"

<<airchar[0][5]<<endl;

cout<<"Row 2\t"<<airchar[1][0]<<"\t"<<airchar[1][1]<<"\t"

<<airchar[1][2]<<"\t"<<airchar[1][3]<<"\t"<<airchar[1][4]<<"\t"

<<airchar[1][5]<<endl;

cout<<"Row 3\t"<<airchar[2][0]<<"\t"<<airchar[2][1]<<"\t"

<<airchar[2][2]<<"\t"<<airchar[2][3]<<"\t"<<airchar[2][4]<<"\t"

<<airchar[2][5]<<endl;

cout<<"Row 4\t"<<airchar[3][0]<<"\t"<<airchar[3][1]<<"\t"

<<airchar[3][2]<<"\t"<<airchar[3][3]<<"\t"<<airchar[3][4]<<"\t"

<<airchar[3][5]<<endl;

cout<<"Row 5\t"<<airchar[4][0]<<"\t"<<airchar[4][1]<<"\t"

<<airchar[4][2]<<"\t"<<airchar[4][3]<<"\t"<<airchar[4][4]<<"\t"

<<airchar[4][5]<<endl;

cout<<"Row 6\t"<<airchar[5][0]<<"\t"<<airchar[5][1]<<"\t"

<<airchar[5][2]<<"\t"<<airchar[5][3]<<"\t"<<airchar[5][4]<<"\t"

<<airchar[5][5]<<endl;

cout<<"Row 7\t"<<airchar[6][0]<<"\t"<<airchar[6][1]<<"\t"

<<airchar[6][2]<<"\t"<<airchar[6][3]<<"\t"<<airchar[6][4]<<"\t"

<<airchar[6][5]<<endl;

cout<<"Row 8\t"<<airchar[7][0]<<"\t"<<airchar[7][1]<<"\t"

<<airchar[7][2]<<"\t"<<airchar[7][3]<<"\t"<<airchar[7][4]<<"\t"

<<airchar[7][5]<<endl;

cout<<"Row 9\t"<<airchar[8][0]<<"\t"<<airchar[8][1]<<"\t"

<<airchar[8][2]<<"\t"<<airchar[8][3]<<"\t"<<airchar[8][4]<<"\t"

<<airchar[8][5]<<endl;

cout<<"Row 10\t"<<airchar[9][0]<<"\t"<<airchar[9][1]<<"\t"

<<airchar[9][2]<<"\t"<<airchar[9][3]<<"\t"<<airchar[9][4]<<"\t"

<<airchar[9][5]<<endl;

cout<<"Row 11\t"<<airchar[10][0]<<"\t"<<airchar[10][1]<<"\t"

<<airchar[10][2]<<"\t"<<airchar[10][3]<<"\t"<<airchar[10][4]<<"\t"

<<airchar[10][5]<<endl;

cout<<"Row 12\t"<<airchar[11][0]<<"\t"<<airchar[11][1]<<"\t"

<<airchar[11][2]<<"\t"<<airchar[11][3]<<"\t"<<airchar[11][4]<<"\t"

<<airchar[11][5]<<endl;

cout<<"Row 13\t"<<airchar[12][0]<<"\t"<<airchar[12][1]<<"\t"

<<airchar[12][2]<<"\t"<<airchar[12][3]<<"\t"<<airchar[12][4]<<"\t"

<<airchar[12][5]<<endl;

cout<<endl;

cout<<"Enter Ticket type (F C, B C, or E C): ";

cin>>ticket;

cout<<"Desired Row: ";

cin>>row[0];

cout<<"Desired seat (A,B,C,D,E or F): ";

cin>>seat;

switch(seat)

{

case 'A':

case 'a':

row[0] = row[0] - 1;

row[1] = 1;

row[1] = row[1] - 1;

break;

case 'B':

case 'b':

row[0] = row[0] - 1;

row[1] = 2;

row[1] = row[1] - 1;

break;

case 'C':

case 'c':

row[0] = row[0] - 1;

row[1] = 3;

row[1] = row[1] - 1;

break;

case 'D':

case 'd':

row[0] = row[0] - 1;

row[1] = 4;

row[1] = row[1] - 1;

break;

case 'E':

case 'e':

row[0] = row[0] - 1;

row[1] = 5;

row[1] = row[1] - 1;

break;

case 'F':

case 'f':

row[0] = row[0] - 1;

row[1] = 6;

row[1] = row[1] - 1;

break;

}

if(ticket == "F C")

{

if(row[0]+1 == 1 || row[0]+1 == 2)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

else if(ticket == "B C")

{

if(row[0]+1 == 3 || row[0]+1 == 4 || row[0]+1 == 5

|| row[0]+1 == 6|| row[0]+1 == 7)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

else if(ticket == "E C")

{

if(row[0]+1 == 8 || row[0]+1 == 9 || row[0]+1 == 10

|| row[0]+1 == 11|| row[0]+1 == 12|| row[0]+1 == 13)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

row[0] = 0;

row[1] = 0;

system("cls");

}

return 0;

}

6 0

3 years ago

Which of the following is NOT an advantage of central management of information systems in the University System of Georgia? (A)

zzz [600]

Answer:

Independence

Explanation:

Management information system (MIS) is the system that acts as the backbone of an organization's activities, holding everything together. According to my research on MIS, I can say that based on the information provided within the question the one term that is not considered an advantage would be Independence. Since MIS doesn't really provide independence since the organization depends on the system.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0

3 years ago