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Naddika [18.5K]
3 years ago
7

Write a function that will alphabetize a string WITHOUT using the sort function :

Computers and Technology
1 answer:
Dimas [21]3 years ago
7 0

Answer:

here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// function to alphabetize the input string

void alphabetize(string &str)

{

// find the length of string

 int n=str.size();

 

  for(int x=0;x<n;x++){

      for(int y=x+1;y<n;y++)

      {  

          //swap the character

          if(str[x]>str[y]){

              char ch=str[x];

              str[x]=str[y];

              str[y]=ch;

          }

      }

  }

 

  cout<<"alphabetize string is: "<<str<<endl;;

 

}

int main()

{// string variable to read input

  string inp;

 

  cout<<"Please Enter a String in lowercase :";

  //reading the input

  cin>>inp;

  // call function with inp argument

  alphabetize(inp);

  return 0;

  }

Explanation:

Declare a variable "inp" of string type and assign the input string to it. call the alphabetize() function with argument "inp".In the alphabetize(),find the length  of input string.Then travers the string and if a character is greater than any  next character in the string then swap it, so that all the character are sorted.

Output:

Please Enter a String in lowercase :helloworld                                                                                                                

alphabetize string is: dehllloorw

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I am writing a Python program. Let me know if you want the program in some other programming language.        

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wordcount("file.txt") #calls wordcount method and passes name of the file to that method

Explanation:

The program has a function wordcount that takes the name of a text file (filename) as parameter.

open() method is used to open the file in read mode. "r" represents the mode and it means read mode. Then a dictionary is created and named as wc. The first for loop, iterates through each line (sentence) of the text file. strip() method is used to remove extra empty spaces or new line character from each sentence of the file, then each sentence is converted to lower case using lower() method to avoid case sensitivity. Now the words "hello" and "Hello" are treated as the same word.

sentence = sentence.translate(sentence.maketrans("", "", string.punctuation))  statement uses two methods i.e. maketrans() and translate(). maketrans() specifies the punctuation characters that are to be deleted from the sentences and returns a translation table. translate() method uses the table that maketrans() returns in order to replace a character to its mapped character and returns the lines of text file after performing these translations.

Next the split() method is used to break these sentences into a list of words. Second for loop iterates through each word of the text file. As its given to ignore words of length 2 or less, so an IF statement is used to check if the length of word is greater than 2. If this statement evaluates to true then next statement: if word in wc:   is executed which checks if the word is already present in dictionary. If this statement evaluates to true then 1 is added to the count of that word. If the word is not already present  then the word is added to the wc dictionary and 1 s assigned to the count of that word.

Next the words along with their occurrences is printed. The program and its output are attached as screenshot. Since the frankenstein.txt' is not provided so I am using my own text file.

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