Question

Question 6 (5 points)

Answer 1

Answer:

2) 284.2 kg

Step-by-step explanation:

Density, mass and volume

We know the density of certain mass m who occupies a volume v is:

$\displaystyle \rho =\frac{m}{v}$

Our hot air balloon holds a volume of 1,592 m^3 of helium. Knowing the density of helium is 0.1785 kg/m^3, we can solve for the mass

$m=\rho v$

$m=(0.1785)(1,592) = 284.172\ kg$

Rounding to the nearest tenth:

$m=284.2\ kg$

The correct option is 2)