Let's apply the formula giving the slope:
m=(y2-y1) /(x2-x1) , let's plug:
m= (8-0) / (3-(-1)) ====> m= 2
Answer:
a. Let the variable be
for the fundraising activities and
as the revenue for foundation.
b. ![M =0.60x](https://tex.z-dn.net/?f=M%20%3D0.60x)
c. $43.2
d. $1416.67
Step-by-step explanation:
Given that:
The World Issues club donates 60% of the total of their fundraising activities.
Answer a.
Let us choose the variable
to represent the money earned during fundraising activities and
for the revenue generated for foundation.
Answer b.
Foundation will receive 60% of the total of the fundraising activities.
Equation to determine the money that will be received by foundation:
![M = 60\%\ of\ x\\OR\\M = 0.6x](https://tex.z-dn.net/?f=M%20%3D%2060%5C%25%5C%20of%5C%20x%5C%5COR%5C%5CM%20%3D%200.6x)
Answer c.
Given that x = $72, M = ?
Putting the value of x in the equation above:
![M = 0.6 \times 72\\\Rightarrow \$43.2](https://tex.z-dn.net/?f=M%20%3D%200.6%20%5Ctimes%2072%5C%5C%5CRightarrow%20%5C%2443.2)
Answer d.
Given that M = $850, x = ?
Putting the value of M in the equation above to find x:
![850= 0.6 \times x\\\Rightarrow x = \dfrac{850}{0.6}\\\Rightarrow x = \$ 1416.67](https://tex.z-dn.net/?f=850%3D%200.6%20%5Ctimes%20x%5C%5C%5CRightarrow%20x%20%3D%20%5Cdfrac%7B850%7D%7B0.6%7D%5C%5C%5CRightarrow%20x%20%3D%20%5C%24%201416.67)
So, the answers are:
a. Let the variable be
for the fundraising activities and
as the revenue for foundation.
b. ![M =0.60x](https://tex.z-dn.net/?f=M%20%3D0.60x)
c. $43.2
d. $1416.67
Solution:
Average time per line = total time / total lines
Average time per line = (3x^2 + 2)/(x + 4)
Average time per line = 3x - 12 + (3x^2 + 2)/50 milliseconds
Answer:
c = -3
Step-by-step explanation:
The discriminant is 73, that means we have:
(-1)^2-4*6*c=73
then: 1-24c=73
or -24c= 73 -1
-24c = 72
Then c = 72/-24= -3
The answer is -3
Hope that useful for you.
Answer:
15 boys
Step-by-step explanation:
There are 27 students. The number of girls is only 4/5 of the number of boys. I started by splitting the class. 14 boys and 13 girls doesn't work, so I changed it to 12 and 15. If it was 12 girls and 15 boys, the girls would have 4/5 of the boys, so it must be 12 girls and 15 boys.