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Vanyuwa [196]
3 years ago
15

What is the percintage change of 36 to 24

Mathematics
1 answer:
REY [17]3 years ago
5 0

Answer:

if its 24 by 36 then its 150%. If it was 36 by 24 then it would be 66.6

Step-by-step explanation:

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Noha, Sarah, and Karima are sisters. Noha is 3 years older than Sarah.
Virty [35]

Answer:

25 years old

Step-by-step explanation:

karima is 20 years old

Sarah is 2 years older than karima (20+2= 22)

Noha is 3 years older than Sarah

if sara is 22 then noha is 22+3=25

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2 years ago
Sara and her dad visit Yo-Yo Yogurt again. This time, the scale says that sara has 14 ounces of vanilla yogurt in her cup. Her f
enot [183]

1.5/16 its the most i can do

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3 years ago
What is the sum of the polynomials?
lesya [120]

Add the like terms:

8x2+x2=9x2

-9y2-3y2=-12y2

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9x2-12y2-11x

Hope this helps!!

5 0
3 years ago
After all of the start-up costs, a company starts with $100 and makes $0.75 on each unit sold. Write a linear equation in slope
KiRa [710]

The answer would most likely be c because you multiply 0.75 by the amount of units sold and find out the profit after adding it.

Hope this helps! :)

4 0
3 years ago
Inequality to x2 < 64
Anarel [89]
              NOT MY WORDS TAKEN FROM A SOURCE!

(x^2) <64  => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2    so    (x^2) - (8^2) < 0  To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y)  You can work backwards and verify this is true. so let's set (x^2) - (8^2)  equal to zero to find the roots: (x^2) - (8^2) = 0   => (x-8)*(x+8) = 0       if x-8 = 0 => x=8      and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0  so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So  -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.

Hope this helped!

:)
7 0
3 years ago
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