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Advocard [28]
3 years ago
13

The limit of tan4x/6x as x approaches 0

Mathematics
1 answer:
AleksandrR [38]3 years ago
5 0
\displaystyle\lim_{x\to0}\frac{\tan4x}{6x}=\lim_{x\to0}\frac{\sin4x}{4x}\times\frac{4x}{6x\cos4x}=\dfrac23\lim_{x\to0}\sec4x=\dfrac23
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Answer:

2.19x=y

Hope this helps!

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2 years ago
A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei
ArbitrLikvidat [17]

Answer:

Part 1) The volume of the paperweight is 576\ cm^{3}

Part 2) The total surface area of the paperweight is 400\ cm^{2}

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the square base

H is the height of the pyramid

B=8^{2}=64\ cm^{2}

H=3\ cm

substitute

V=\frac{1}{3}(64)(3)=64\ cm^{3}

step 2

Find the volume of the cube

The volume of the cube is equal to

V=b^{3}

V=8^{3}=512\ cm^{3}

step 3

Find the volume of the paperweight

64\ cm^{3}+512\ cm^{3}=576\ cm^{3}

Part 2) what is the total surface area of the paperweight?​

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

SA=5b^{2}

SA=5(8^{2})=320\ cm^{2}

step 2

Find the lateral area of the pyramid

LA=4[\frac{1}{2}bh]

LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}

step 3

Find the total surface area of the paperweight

320\ cm^{2}+80\ cm^{2}=400\ cm^{2}

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3 years ago
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In circle C, r = 32 units.
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The greatest integer function, shown below, is defined to be the greatest___ less than or equal to x.
Nataly_w [17]

Answer:

Integer

Step-by-step explanation:

The greatest integer function, F(x)=[[x]], is defined to be the greatest <u>integer that is </u>less than or equal to x.

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