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3 years ago

6

What number should be added to 77 to make the sum 0?

2 answers:

labwork [276]3 years ago

5 0

You should add -77 to 77 because it will cancel out.

andrey2020 [161]3 years ago

4 0

Additive inverses are two numbers that add to 0.
0 is the additive inverse of 0 since 0 + 0 = 0.
For all positive and negative numbers, to find the additive inverse of a number, change its sign.
The additive inverse of 1 is -1.
The additive inverse of 100 is -100.
The additive inverse of -9.5 is 9.5.
In this problem, the additive inverse of 77 is -77.

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The one i chose is wrong i think help.

const2013 [10]

Answer:

You are correct

Step-by-step explanation:

collinear means that they are on the same line, so they are collinear because of the definition of collinear

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3 years ago

Elaine is 8 years younger than her brother Tyler. The sum of their ages is 34. Define a variable and then write and solve an equ

Damm [24]

Answer: Elaine=13 years old Tyler=21 years old

Step-by-step explanation:

Let x = Elaine's age, so her brother Tyler's age = x+8

Elaine+Tyler=34

x+(x+8)=34

2x+8=34

2x=26

x=13

Elaine=13 years old

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3 years ago

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

marissa [1.9K]

Complete question:

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

what is the area of the sector?

Answer:

The area of the sector = $\frac{\pi}{2}$ square units

Step-by-step explanation:

To find the area of the sector of a circle, let's use the formula:

$A = \frac{1}{2} r^2 \theta$

Where, A = area

r = radius = 3

$\theta = \frac{1}{9}\pi$

Substituting values in the formula, we have:

$A = \frac{1}{2}*3^2* \frac{1}{9}\pi$

$A = \frac{1}{2}*9* \frac{1}{9}\pi$

$A = 4.5 * \frac{1}{9}\pi$

$A = \frac{\pi}{2}$

The area of the sector = $\frac{\pi}{2}$ square units

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3 years ago

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Masja [62]

Answer:

mee

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

(X-2)²+(y-1)²=25 how do you do this problem?

Tasya [4]

$(x-x_c)^2+(y-y_c)^2=r^2\\
(x_c,y_c) - \text{center}\\\\
(x-2)^2+(y-1)^2=25\\
\text{center}=(2,1)\\
r=\sqrt{25}=5$

5 0

3 years ago