Supervisor: "Because you are working a late shift, you will get an increase in your wage. You will get an additional 10% per hour from 6:00 PM to 12:00 AM and additional 15% from 12:00 AM to 1:00 AM." Employee: "I am working from 2:00 PM to 12:00 AM. Between 2:00 PM and 6:00 PM, I will make $12.00 per hour. Between 6:00 PM and 12:00 AM, I will make __________ per hour

Answer:

I will make $13.2 per hour

Explanation:

It can be deducted from the question that that the money Employee gets money for Working from 2.00 PM to 6.00 PM = $12per hour

Also the Employee gets additional 10% of money for working from 6.00 PM to 12.00 AM which implies that

10% = (10/100)*$12per hour

=$1.2per hour

Again, Employee gets additional 15% of the money for working from 12.00 AM to 01.00 AM which can be calculated as:

15% = (15/100)*$12per hour

=$1.8 per hour

which means that Employee gets additional $1.8 per hour

of the money for working from 12.00 AM to 01.00 AM

Therefore, if Employee works from 2.00 PM to 12.00 AM,

Employee will gets money for Working from 2.00 PM to 6.00 PM as well as the 10\% extra wage which

= $12 + $1.2 = $13.2

= \$ 12 + \$ 1.2 = \$ 13.2

7 0

3 years ago

Suppose matrix product AB is defined. (a) If A is 4 x 7 and B is a column matrix, give the dimensions of B and AB. [4 marks] (b)

Lesechka [4]

Answer:

(a) Order of matrix B is 7 × 1 and order of matrix AB is 4 × 1.

(b) Order of matrix A is 5 × 5.

Step-by-step explanation:

The product of two matrices is possible if and only if column of first matrix is equal to row of second matrix.

If A is an n × m matrix and B is an m × o matrix, their matrix product AB is an n × p matrix,

(a)

It is given that order of matrix A is 4 x 7.

B is a column matrix. It means the number of column in matrix B is 1.

Let the order of matrix B = n × 1

Product of matrices A and B is possible if and only if column of matrix A is equal to row of matrix B.

$n=7$

Order of matrix B is 7 × 1

$A_{4\times 7}B_{7\times 1}=AB_{4\times 1}$

Order of matrix AB is 4 × 1.

(b)

Order of matrix B = 5 × 5

It is given that A is the identity matrix.

Identity matrix is a square matrix having 1s on the main diagonal, and 0s everywhere else.

So, order of matrix A is equal to order of matrix B.

Order of matrix A = 5 × 5

Therefore order of matrix A is 5 × 5.

(c)

Order of matrix A = 4 × 5

Order of matrix AB = 4 × 7

Let Order of matrix B = n × m

$A_{4\times 5}B_{n\times m}=AB_{4\times 7}$

Product of A and B are possible if and only if n=5.

$A_{4\times 5}B_{5\times m}=AB_{4\times 7}$

$AB_{4\times m}=AB_{4\times 7}$

On comparing both sides, we get

$m=7$

Therefore the order of matrix B is 5 × 7.

6 0

3 years ago

HELP, which function has the least change

const2013 [10]

Answer:

44,39,87,48,09,74,20,09,57,19,85

4 0

3 years ago