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Scilla [17]
3 years ago
7

enson is picking out what to wear to school. He has three clean T-shirts: one white, one red, and one orange. He also has two cl

ean pairs of jeans: one blue and one gray. The tree diagram shows the different outcomes of picking a pair of jeans and a T-shirt. What is the missing color in the diagram? A. blue B. orange C. red D. white

Mathematics
1 answer:
Alenkinab [10]3 years ago
6 0
The missing color is D. white.
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Please answer a and c
n200080 [17]

add the numbers on both side by 3

4 + 3 = 7

8 + 3 = 11

rewrite the expression

7<11

that is still true

do the same by multiplying it by 2 and rewrite the inequality


5 0
3 years ago
Xhoose the word incorectlycomplete the sntence
Semenov [28]
This question needs more information
7 0
3 years ago
Which of the following is a step in simplifying the expression-
Vladimir [108]
The correct answer would be C
8 0
3 years ago
Read 2 more answers
X=3 y=5 z=-2<br> Please help me with number 10
zlopas [31]

Answer:

26

Step-by-step explanation:

2*3*5-3(-2)+5(-2)

6*5+6-10

30+6-10

36-10

26

3 0
2 years ago
Read 2 more answers
What percentage of babies born in the United States are classified as having a low birthweight (&lt;2500g)? explain how you got
lawyer [7]

Answer:

2.28% of babies born in the United States having a low birth weight.

Step-by-step explanation:

<u>The complete question is</u>: In the United States, birth weights of newborn babies are approximately normally distributed with a mean of μ = 3,500 g and a standard deviation of σ = 500 g. What percent of babies born in the United States are classified as having a low birth weight (< 2,500 g)? Explain how you got your answer.

We are given that in the United States, birth weights of newborn babies are approximately normally distributed with a mean of μ = 3,500 g and a standard deviation of σ = 500 g.

Let X = <u><em>birth weights of newborn babies</em></u>

The z-score probability distribution for the normal distribution is given by;

                          Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 3,500 g

            \sigma = standard deviation = 500 g

So, X ~ N(\mu=3500, \sigma^{2} = 500)

Now, the percent of babies born in the United States having a low birth weight is given by = P(X < 2500 mg)

         

   P(X < 2500 mg) = P( \frac{X-\mu}{\sigma} < \frac{2500-3500}{500} ) = P(Z < -2) = 1 - P(Z \leq 2)

                                                                 = 1 - 0.97725 = 0.02275 or 2.28%

The above probability is calculated by looking at the value of x = 2 in the z table which has an area of 0.97725.

4 0
3 years ago
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