For fog or f(g(x)), plug g(x) into f(x):
2(3x+2)²+x
Then simplify:
2( (3x+2)(3x+2) )+x
2( 9x²+12x+4 )+x
18x²+24x+8 +x
18x²+25x+8
Then you can simplify this further using factoring methods to:
(2x+1)(9x+8)
Hope this helps!! :)
10^-10 in decimal form is 0.000000001. Because the exponent is negative, you move the decimal point ( decimal point is at the end of 0 of the base number 10) 10 place to the right of 10 and u get the answer above. I discarded the 0 later in the answer because now that you've moved the decimal, that 0 have no value. But when forming it in decimal you have to use that 0 or you will get a wrong answer, instead of eight 0's, you will end up with nine 0's.
you cannot show too much "work"
basically, you remove what is common to all of the factors, and then put brackets, as it will be multiplied back in, remember that when you multiply exponents with the same base, its same as adding them, so subtract to remove...
you can seperate two of the variables , then factor, then subtract the last one from those two, because it cannot be factored out , as in part2 #2
