A "solution" would be a set of three numbers ... for Q, a, and c ... that
would make the equation a true statement.
If you only have one equation, then there are an infinite number of triplets
that could do it. For example, with the single equation in this question,
(Q, a, c) could be (13, 1, 2) and they could also be (16, 2, 1).
There are infinite possibilities with one equation.
In order to have a unique solution ... three definite numbers for Q, a, and c ...
you would need three equations.
18 hope it helped!!
:) be my pleasure!
tysm
Answer:
Step-by-step explanation:
Given that,
y' = 17y ( 1-y^7)
Let y=1
Then, y' = 0 for all t
Then show that it is the only stable equilibrium point so that as y→1, t→∞ with any initial value.
So, the graph solution will be
y(0) = 1 and this will be an horizontal line
If, y(0) > 1 then, y' < 0 by inspecting the first equation, so the graph is has decreasing solution.
Likewise, if y(0) < 1 then, y' > 0 and the graph is increasing.
So no matter the initial condition, graph of the solution will be asymptotic to the horizontal line above.
This make the limit be 1.
This shows that x = 1 is a stable equilibrium.
Answer:
1/6 p -4/5
Step-by-step explanation:
- 2/3p + 1/5 - 1 + 5/6p
When I combine like terms, I put them next to each other.
- 2/3p + 5/6p+ 1/5 - 1
We need to get a common denominator of 6 for the p terms
-2/3 *2/2 p + 5/6 p
-4/6p + 5/6 p
1/6 p
We need to get a common denominator of 5 for the contant terms
1/5 - 1*5/5
1/5-5/5
-4/5
Substituting these in
2/3p + 5/6p+ 1/5 - 1
1/6 p -4/5
The answer is :
23 3/8 can be written as 23.375
