Answer:
![{27}^{ \frac{1}{3} } = \sqrt[3]{27} = \sqrt[3]{3 \times 3 \times 3} = \boxed{ 3}✓](https://tex.z-dn.net/?f=%20%7B27%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B27%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B3%20%5Ctimes%203%20%5Ctimes%203%7D%20%20%3D%20%5Cboxed%7B%203%7D%E2%9C%93)
<h3>3. <em><u>3</u></em> is the right answer.</h3>
Answer:4x2−6x−4
Step-by-step explanation:
(4x+2)(x−2)
=(4x+2)(x+−2)
=(4x)(x)+(4x)(−2)+(2)(x)+(2)(−2)
=4x2−8x+2x−4
=4x2−6x−4
If you draw the line and mark -2 and 3 you find that they are 5 apart. By calculation, subtract the lowest from the highest: 3 - -2 = 3+2 = 5
<span>A center-seeking force related to acceleration is centripetal force. The correct option among all the options that are given in the question is the first option or option "A". It is actually a force acting on a body that is moving in a circular path and its direction is towards the center. I hope the answer has helped you.</span>
Make 3 2/9 improper fraction
3 2/9 = 29/9
29/9 * 3/5 = 87/45 = 29/15
The answer is 29/15
