Which of the following statements have the same result? Explain each step in solving each one.

1 answer:

4 0

First: f(2) is same as f(x=2) so all we have to do is to express x=2 in f(x)
f(2) = 3*2 + 2 = 8

Second
f^(-1) (3) is inverse function. first we solve f(x) for x.
let f(x) be equal to some variable m
m = (2x -7)/3
3m = 2x - 7
2x = 3m + 7
x = (3m + 7)/3
now we write:
f^-1(x) = (3x + 7)/3

x=3
f^-1(3) = 16/3

Third
2y + 14 = 4y - 2
we just solve for y
2y = 16
y = 8

Now we take that f(x) = y because we both write to be the functions of x

that means that First and third have same result.

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Substitute this into the parabolic equation,

$k-x=6-(x-3)^2\implies x^2-7x+(k+3)=0$

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$(-7)^2-4(k+3)=49-4(k+3)>0\implies k$

We can tell from the quadratic equation that $C$ has its vertex at the point (3, 6). Also, note that

$-1\le\sin t\le1\implies3\le3+2\sin t\le5\implies3\le x\le5$

and

$-1\le\cos2t\le1\implies2\le4+2\cos2t\le6\implies2\le y\le6$

so the furthest to the right that $C$ extends is the point (5, 2). The line $x+y=k$ passes through this point for $2+5=k\implies k=7$ . For any value of $k$ , the line $x+y=k$ passes through $C$ either only once, or not at all.