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stira [4]
3 years ago
12

In the given right triangle, find the missing length to the nearest tenth.

Mathematics
1 answer:
NemiM [27]3 years ago
5 0
Use pythagorean's theorem to solve for missing sides of a right triangle.

a^2 + b^2 = c^2

a = 11
b = 17
c = We don't know yet so I'll call it x

11^2 + 17^2 = c^2

121 + 289 = c^2

410 = c^2

c = √410

c = 20.2

Thus, the answer is B.

Hope this helps, and May the Force Be With You!

-Jabba
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1.75x100=175

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A line contains the points (3, 8) and (6, 5). Write the equation of the line in slope-intercept form. Use no spaces in your equa
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What is the answer to 56,763 rounding to the nearest thousand
nika2105 [10]

Answer:

60000

Step-by-step explanation:

56763 so you're going to take that number and you're going to run it to the nearest thousands by doing that you're going to take the six and six is either closest to zero or 10 and it is closer to 10 which would be your answer so you're going to add these zero replacing the six seven six and three in the equation and making me five of six by adding the one from the number 10 if you have any other questions text me if that doesn't make sense

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Read 2 more answers
PLEASE HELP!!!! about solving systems!!! 30 points!!!
e-lub [12.9K]

Answer:

Step-by-step explanation:

<h2>d ) 13x−8y=28 11x−8y=24 </h2>

we can solve:

13x−8y=28

11x−8y=24

.............................(subtract side by side)

13x - 11 x + (-8y) - (-8y) = 28 - 24

2x + 0 = 4

x = 4/2 = 2 (divide both sides by 2),

then you replace x = 2 into 13x - 8y = 28, we have 26 - 8y = 28

or -8y = 28-26, or -8y = 2, then y = 2/ -8= -1/4

Solution x =2, y = - 1/4

b) 5x−2y=1 15x−3y=−3

5x−2y=1 (multiple bothe sides by 3)

15x−3y=−3

we have

15x−6y=3

15x−3y=−3

..................(  subtract side by side)

0 -3y = 6

y = 6/-3

y = -2

then you replace y =- 2 into 5x - 2y = 1, we have 5x + 4 = 1

or 5x = 1-4 or 5x = -3, then x = -3/5

Solution: x = -3/5, y = -2

c) 13x−12y=14 11x−4=18y

we have:

13x−12y=14

11x−4=18y

then:

13x−12y=14 ( multiple bothe sides by 6)

11x - 18y = 4   (multiple bothe sides by 4)

then

78x−72y=84

44x−72y= 16

...........................( subtract side by side)

34x = 68

or x = 68/34 = 2

then you replace x = 2 into 11x -4 = 18y , we have 22 -4 = 18y

or 18y = 18 or y = 18/18 = 1

Solution: x = 2 , y = 1

a) 12x−7y=2 4x−5y=6

we have

12x−7y=2

4x−5y=6  (multiple bothe sides by 3)

so

12x−7y=2

12x−15y=18

-------------------------(subtract side by side)

8y = -16

or y = -16/8 = -2

then you replace y = -2 into 4x -5y = 6 , we have 4x + 10 = 6

or 4x = 6 - 10 or 4x = - 4 and x = -4/4 = - 1

Solution: x = - 1 , y = - 2

b) 7u+2v=1 17u+6v=−9

7u+2v=1   (multiple bothe sides by 3)

17u+6v=−9

so

21u+6v=3  

17u+6v=−9

------------------(subtract side by side)

4u = 12

or u = 12/4 = 3

then you replace u = 3 into 7u +2v = 1 , we have 21 + 2v = 1

or 2v = 1 - 21 or 2v = - 20 and v = -20/2 = - 10

Solution: u = 3, v = - 10

<h2>c) 6x=25y+1 5x−16y=−4</h2>

6x=25y+1  (multiple bothe sides by 5)

5x−16y=−4  (multiple bothe sides by 6)

we have

30x=125y+5

30x = 96y−24

-------------------------(subtract side by side)

0 = 29y + 29

or 29y = - 29

then y = - 29/29 = -1

then you replace y = -1 into 6x = 25y + 1 , we have 6x = - 25 + 1

or 6x = - 24 or x = -24/6 = - 4

Solution: x= -4, y = - 1

Have a good day!

6 0
3 years ago
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