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Rashid [163]
3 years ago
9

I want to check if mine is right, if not please solve​

Mathematics
2 answers:
Kruka [31]3 years ago
8 0

Answer:

i think it is crrect

Step-by-step explanation:

Karolina [17]3 years ago
6 0

Answer: it right

Step-by-step explanation:

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andrew11 [14]

Answer:

how is this mathematics lol

Step-by-step explanation:

4 0
3 years ago
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the x and y axis are tangent to a circle with radius 3 units. write a standard equation of the circle.
Mekhanik [1.2K]

Given:

The x and y axis are tangent to a circle with radius 3 units.

To find:

The standard form of the circle.

Solution:

It is given that the radius of the circle is 3 units and x and y axis are tangent to the circle.

We know that the radius of the circle are perpendicular to the tangent at the point of tangency.

It means center of the circle is 3 units from the y-axis and 3 units from the x-axis. So, the center of the circle is (3,3).

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of the circle and r is the radius of the circle.

Putting h=3,k=3,r=3, we get

(x-3)^2+(y-3)^2=3^2

(x-3)^2+(y-3)^2=9

Therefore, the standard form of the given circle is (x-3)^2+(y-3)^2=9.

3 0
3 years ago
Help plz...................................
N76 [4]

Answer:

12

Step-by-step explanation:

These are similar triangles, so the ratio of their sides is the same for each side.

AB = 8  and  BD = 10

So, the ratio is 8:10   or   4:5

Because the triangles are similar....

The ratio of AC:CE  is also  4:5

12:15 = 4:5

So, 12 is the answer!

8 0
3 years ago
Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


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3 years ago
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Answer:

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