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4 years ago

What are the solutions to the equation? x^2−12x+36=4 x1= x2= (not multiple choice)

Mathematics

1 answer:

choli [55]4 years ago

6 0

Answer:

x1=4

x2=8

Step-by-step explanation:

1- Factor the equation.

2- solve a Single Variable Equation

3- Parabola, Finding the Vertex

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kelly subscribes to a service called mysongs for downloading music she pays a $7 fee each month to download an unlimited numbers

Nastasia [14]

subtract the fee from the total to get the amount actually spent on songs

23.80-7 = 16.80

divide that amount by price per song to get number of songs downloaded

16.80 /0.20 = 84 songs

8 0

3 years ago

In right ∆ABC with m∠B=30°, AC = 4.<br> Find AB, HB and Area of triangle ABC

alexdok [17]

Answer:

hb=4√3

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

A 70" TV is advertised on sale at a local store. What are the length and width of the television?

a_sh-v [17]

The length and width of the television could be any two numbers whose product is 70.

7 0

4 years ago

A cell phone company $500 for a new phone and $60 for a monthly plan. If C(t) is a rational function that represents the average

lisov135 [29]

The range of a function is the set of possible values that can be obtained from the dependent variable. The range of the function is: $R: (500, \infty)$

Given that:

$Phone = \$500$

$Monthly\ Plan = \$60$

Let the number of months be t. So, the function C(t) is calculated as follows:

$C(t) = Phone + Monthly\ Plan \times t$

$C(t) = 500 + 60 \times t$

$C(t) = 500 + 60t$

The range is calculated as follows:

The smallest possible value of t is 0 i.e. when no monthly subscription is done.

So, we have:

$C(0) = 500 + 60\times 0= 500 + 0 = 500$

And the highest is $\infty$ i.e. for a large value of t

So, we have:

$C(\infty) = 500 + 60\times \infty= 500 + \infty = \infty$

Hence, the range of the function is:

$R: (500, \infty)$

Read more about range of functions at:

brainly.com/question/13824428

5 0

3 years ago

HELP help HELP help HELP help HELP help HELP help HELP help HELP help

Morgarella [4.7K]

$\text{mass of freight train} = 9.98 \times {10}^{6} kg$

$\text{mass of aircraft carrier} = 7.3 \times {10}^{7} \: kg$

$\text{difference of masses of aircraft and train: } \\ \\ 7.3 \times {10}^{7} - 9.98 \times {10}^{6} \\ \\ = 73 \times {10}^{6} - 9.98 \times {10}^{6}$

$= (73 - 9.98 )\times {10}^{6} \\ \\ = 63.02 \times {10}^{6} \\ \\ = 6.302 \times {10}^{6} \: kg \\ \\ \approx 6.3 \times {10}^{6} \: kg$

Approximately, aircraft carrier is 6.3 × 10^6 kg heavier than the freight train.

7 0

3 years ago