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Jlenok [28]
4 years ago
12

What are the solutions to the equation? x^2−12x+36=4 x1= x2= (not multiple choice)

Mathematics
1 answer:
choli [55]4 years ago
6 0

Answer:

x1=4

x2=8

Step-by-step explanation:

1- Factor the equation.

2- solve a  Single Variable Equation

3- Parabola, Finding the Vertex

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The width of a rectangle is the length minus 3 units. The area of the rectangle is 10 units. What is the width, in units, of the
solmaris [256]

Answer:

2 units

Step-by-step explanation:

because the only whole number factor pair to 10 is 2x5 and luckily, it turned out that 5-3=2, so there are no decimals or fractions. Yay!

8 0
3 years ago
100% with 8 equal parts
bulgar [2K]

Are you asking what the 8 equal parts are ? If so 100/8=12.5

4 0
3 years ago
8. What are the advantages of switching a quadratic function from standard form into vertex form?
Airida [17]

Answer:

vertex form automatically gives you your vertex and your y intercept so all you need to do is graph. Hope this helps

Step-by-step explanation:

3 0
3 years ago
Solve the system by substitution.<br> y = 8x<br> y=10x – 4<br> Submit Answer<br> How
Goshia [24]

Answer:

(2,16)

Step-by-step explanation:

y=8x-----------(i)

y= 10x-4---------(ii)

Substituting the value of y=8x in equation (ii)

8x=10x-4

8x-10x=-4

-2x= -4

x=2

Now, substituting the value of x= 2 in equation (i)

y=8x=8(2)=16

Solution of the system is (2,16)

6 0
3 years ago
ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ДАЮ 23 ОЧКА!!!
posledela

(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 <em>y</em> ², radius <em>y</em>, and thickness ∆<em>y</em>, thus contributing an area of 2<em>π</em> <em>y</em> (3 - 3/4 <em>y</em> ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ <em>y</em> ≤ 2, thus given by the integral

\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 <em>x</em>), thus contributing an area of <em>π</em> (√(4/3 <em>x</em>))² = 4<em>π</em>/3 <em>x</em>. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ <em>x</em> ≤ 3, or by the integral

\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi

Using either method, the volume is 6<em>π</em> ≈ 18,85. I do not know why your textbook gives a solution of 90,43. Perhaps I've misunderstood what it is you're supposed to calculate? On the other hand, textbooks are known to have typographical errors from time to time...

8 0
3 years ago
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