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3 years ago

I need help on this please

Mathematics

1 answer:

tia_tia [17]3 years ago

3 0

9514 1404 393

Answer:

B 2/6

Step-by-step explanation:

2 of the 6 possible outcomes are ones that are of interest. A "fair" die means the mutually-exclusive outcomes have equal probability, so ...

P(4 or 5) = P(4) +P(5) = 1/6 + 1/6 = 2/6

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-3x+y=-3<br> How do I write this in y=Mx+b form?

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3 years ago

4y(2 + y) - (3y +3)<br> HELPPP

kati45 [8]

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8y + 4y² - 3y - 3

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3 0

3 years ago

Read 2 more answers

Please look at the image provided.

SpyIntel [72]

Answer:

$x=3$

Step-by-step explanation:

$\frac{6\left(x-2\right)}{2}=\frac{3\left(x+5\right)}{8}\\\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c\\6\left(x-2\right)\cdot \:8=2\cdot \:3\left(x+5\right)\\Simplify\\48\left(x-2\right)=6\left(x+5\right)\\\mathrm{Expand\:}48\left(x-2\right):\quad 48x-96\\48\left(x-2\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=48,\:b=x,\:c=2\\=48x-48\cdot \:2\\\mathrm{Multiply\:the\:numbers:}\:48\cdot \:2=96$

$=48x-96\\\mathrm{Expand\:}6\left(x+5\right):\quad 6x+30\\6\left(x+5\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=6,\:b=x,\:c=5\\=6x+6\cdot \:5\\\mathrm{Multiply\:the\:numbers:}\:6\cdot \:5=30\\=6x+30\\48x-96=6x+30\\\mathrm{Add\:}96\mathrm{\:to\:both\:sides}\\48x-96+96=6x+30+96\\Simplify\\48x=6x+126\\\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}\\48x-6x=6x+126-6x\\\mathrm{Simplify}\\42x=126\\\mathrm{Divide\:both\:sides\:by\:}42$

$\frac{42x}{42}=\frac{126}{42}\\Simplify\\x=3$

8 0

3 years ago