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netineya [11]
2 years ago
6

Leena knits 10 rows in 12 minutes.

Mathematics
2 answers:
maria [59]2 years ago
4 0

Answer:

It will take 30 minutes!

Hope this helps! :D

Step-by-step explanation:

Mama L [17]2 years ago
3 0
30 minutes
Since 10 rows=12 minutes
10rows + 10rows = 20 since each 10 rows is 12 minutes it’s
12 minutes+ 12 minutes = 24
But we still have the 5 rows so that would be have of 12 minutes and that’s 6 minutes so
24 minutes plus the 6 minutes is
30 minutes
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Find the lengths of the missing side . Simplify all radicals !!!<br> help mee!!!!!!
larisa86 [58]

Answer:

e = 13\sqrt{2}

f = 13\sqrt{2}

Step-by-step explanation:

The ∆ given is an isosceles ∆ with a right angle measuring 90°, and two congruent angles measuring 45° each.

Using trigonometric ratio formula, we can find the lengths of the missing side as shown below:

Finding e:

sin(\theta) = \frac{opp}{hyp}

sin(\theta) = sin(45) = \frac{\sqrt{2}}{2}

hyp = 26

opp = e = ?

Plug in the values into the formula

\frac{\sqrt{2}}{2} = \frac{e}{26}

Multiply both sides by 26

\frac{\sqrt{2}}{2}*26 = \frac{e}{26}*26

\frac{\sqrt{2}}{2}*26 = e

\frac{\sqrt{2}}{1}*13 = e

13\sqrt{2} = e

e = 13\sqrt{2}

Since side e is of the same length with side f, therefore, the length of side f = 13\sqrt{2}

3 0
3 years ago
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ololo11 [35]

Answer:

Step-by-step explanation:

(0, -1) (3,3)

(3 + 1)/(3 - 0) = 4/3

y + 1 = 4/3(x - 0)

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3 years ago
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Answer:

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Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.
leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

12x-5y+14=0 \\ 12x-5y-14=0

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1

\Rightarrow 12h-5k-1=\pm 13

\Rightarrow 12h-5k=\pm 14

\Rightarrow 12h-5k=14,\ 12h-5k=-14

\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0

\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0

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2 years ago
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Stells [14]

Answer:

I gotcha.

Step-by-step explanation:

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<h2>there</h2>
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3 years ago
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