Devon and Michael ran a 5-mile race. Devon ran 2 miles per hour faster than Michael and finished the race 5 minutes before Micha
el did. If x represents Michael's speed (in miles per hour), which equation could represent this situation? Answer Choices 5x+2−5x=112 5x−5x+2=112 x+25−x5=112 x+25+x5=112 Part 2 What was Michael's speed? miles per hour
Let x------------> Michael's speed <span>(in miles per hour) y------------> </span>Devon's speed (in miles per hour)
we know that y=x+2-------> equation 1 speed=distance/time--------> time=distance/speed distance =5 miles Michael's time=5/x Devon's time=5/y the difference [Michael's time-Devon's time]= 5 minutes
1 hour--------> 60 min x-------------> 5 min x=5/60 hour
5/x-5/y=5/60-----------> multiply by 60 both members 300/x-300/y=5-------> (300/x)-5=300/y-------> (300-5x)/x=300/y y/300=x/(300-5x)------> y=300x/(300-5x)-----> y=60x/(60-x)-----> equation 2
using a graph tool ----->to resolve the second order equation the solution is x=10 then Michael's speed is 10 miles/hour Devon's speed is 10+2-----> 12 miles/hour
