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docker41 [41]
3 years ago
11

A recipe calls for ​ ​1 /4 ​​ start fraction, 1, divided by, 4, end fraction cup of chocolate chips for each batch of cookies. A

lonzo has 1/2 ​​ start fraction, 1, divided by, 2, end fraction cup of chocolate chips. How many batches of cookies can Alonzo make?
Mathematics
1 answer:
Neko [114]3 years ago
6 0

Answer:

2

Step-by-step explanation:

1/2 cup = 2/4 cups = 2 × 1/4 cup

Alonzo can make 2 batches that each require 1/4 cup.

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9) v - 15 = -27 10) n + 16 = 9
Alik [6]

Answer:

9) v= -12  

10) n= -7

Step-by-step explanation:

9) v - 15 = -27

Add 15 from both sides

i.e. v - 15 + 15 = -27 + 15

v = -12

10) n + 16 = 9

Subtract 16 from both sides

i.e. n + 16 - 16 = 9 - 16

n = -7

Hope this helps!!!

5 0
3 years ago
Can anyone help me on this one?
sertanlavr [38]

Answer:

6

Step-by-step explanation:

a=1/2 b*h

a=1/2 3*4

a=1/2 12

a=6

:)

7 0
3 years ago
Read 2 more answers
Members of the Video Digital club produce short videos. At the end
allsm [11]

Answer:

hggggggggjrhg

Step-by-step explanation:

fhhhhhhhgtrhrehr this is the right answer

5 0
3 years ago
The scale of a map is 2 in = 7 feet. If the map distance is 11 inches what is the actual distance. Be sure to include label!
Arte-miy333 [17]
38.5 feet because one inch is 3.5 feet
4 0
3 years ago
Read 2 more answers
How much of a 60% saline solution would you need to add to pure water to create 10 L of a 50% saline solution ?
Julli [10]
So say, we add "x" of the 60% saline solution, now, how much salt is in that solution?  now 60% is salt but the rest is something else, but only salt is 60% of "x", or (60/100) * x, or 0.6x.

likewise, for the 10 Liters, if only 50% is salt, then is just (50/100) * 10 or 5.

now... let's check the water whilst we add "y" amount, the water has no salt at all, freshwater for that matter, so, salinity is 0%.  or (0/100) * y or 0.

\bf \begin{array}{lccclll}
&\stackrel{liters}{amount}&\stackrel{\textit{\% of salt}}{quantity}&\stackrel{\textit{total salt}}{quantity}\\
&------&------&------\\
\textit{60\% sol'n}&x&0.60&0.6x\\
\textit{pure water}&y&0.00&0y\\
------&------&------&------\\
mixture&10&0.50&5
\end{array}

\bf \begin{cases}
x+y=10\\
0.6x+0y=5
\end{cases}
\\\\\\
0.6x=5\implies x=\cfrac{5}{0.6}\implies x=\cfrac{25}{3}\implies x=8\frac{1}{3}
7 0
3 years ago
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