Question

Ωωωωωωωωωωωωωωωωω WILL GIVE BRAINLIESTEET Given: ∆ABC, AB = 45 AC = CB = 34 Find: m∠B

Answer 1

Answer:

$48.5654 \textdegree$

Step-by-step explanation:

Let $D$ be the mid point of $AB$

Now in $\Delta ACD\ and\ \Delta BCD$

$AC=CB \ (given)\\CD=CD \ (common\ side)\\AD=DB \ (D\ is\ mid\ point\ of\ AB)$

$Hence\ \Delta ACD\cong\Delta BCD$

$\angle A=\angle B\\\angle ACD=\angle BCD\\\angle ADB=\angle BDC$

$\angle ADB+\angle BDC=180\\2\angle ADB=180\\\angle ADB=90$

$in \Delta BCD\\\cos\angle B=\frac{BD}{BC}\\ =\frac{45}{2\times34}\\ =\frac{45}{68} \\\angle B=\cos^{-1}(\frac{45}{68} )\\\angleB=48.5654\textdegree$