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Mademuasel [1]
3 years ago
6

How many 4-digit numbers are neither multiples of 2 nor multiples of 5?

Mathematics
2 answers:
Ugo [173]3 years ago
7 0

Answer:

7,200

Step-by-step explanation:

from 1000-1095 there are 20 multiples of 5

from 1100-1195 there are 20 multiples of 5

from 1200-1295 there are 20

from 1300-1395 there are 20

from 1400-1495 there are 20

from 1500-1595 there are 20

from 1600-1695 there are 20

from 1700-1795 there are 20

from 1800-1895 there are 20

from 1900-1995 there are 20

from 1000-1995 there are 10*20=200 multiples of 5

from 2000-2995 there are 200 multiples of 5

from 3000-3995 there are 200

from 4000-4995 there are 200

from 5000-5995 there are 200

from 6000-6995 there are 200

from 7000-7995 there are 200

from 8000-8995 there are 200

so far there are 8*200=1600 multiples of 5

from 9000-9095 there are 20 multiples of 5

from 9100-9195 there are 20

from 9200-9295 there are 20

from 9300-9395 there are 20

from 9400-9495 there are 20

from 9500-9595 there are 20

from 9600-9695 there are 20

from 9700-9795 there are 20

from 9800-9895 there are 20

from 9900-9999 there are 20

there are another 10*20=200 multiples of 5 to be added to the already 1600 multiples of 5

1600+200=1800 multiples of 5 that are 4-digit numbers

there are 9000 4-digit counting numbers

9000-1800=7200 4-digit numbers that are not multiples of 5

YW BOIZZZZZ :3

andriy [413]3 years ago
4 0

Answer:

There are 7,200

Step-by-step explanation:

Hope this helps!

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8 0
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Read 2 more answers
1/8 (3d-2) = 1/4 (d+5)
tatiyna
OK, so for this equation, your goal is to get the d, and ONLY the d, on one side of the equation. So, to start out, you need to multiply the entire equation, meaning both sides, by 8 because we are trying to get rid of those pesky fractions.
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Step-by-step explanation:

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