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poizon [28]
3 years ago
9

It took14 min to walk around the block 4times. What was her unit rate?

Mathematics
2 answers:
Harman [31]3 years ago
6 0
The unit rate is <span>3.5.</span>
Luba_88 [7]3 years ago
3 0
7.5 min per walk around the block
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Use slope-intercept form, y = mx + b to find the equation of the line that passes through the points (−6, 1) and (3, 4).
Nitella [24]

Answer:

<h3>Y=1/3x+3</h3>

Step-by-step explanation:

To solve this problem, first, you have to use the slope formula of y₂-y₁/x₂-x₁=rise/run. Remember to solve this problem, use slope-intercept form of y=mx+b.

m represents the slope.

b represents the y-intercept.

Y₂=4

Y₁=1

X₂=3

X₁=(-6)

Solve & simplify.

\displaystyle \mathsf{\frac{4-1}{3-(-6)}=\frac{3}{9}=\frac{3\div3}{9\div3}=\frac{1}{3}    }}

The slope is 1/3.

Y-intercept is 3.

y=1/3x+3

In conclusion, the correct answer is y=1/3x+3.

4 0
3 years ago
An amusement park studied methods for decreasing the waiting time (minutes) for rides by loading and unloading riders more effic
Digiron [165]

Answer:

see explaination

Step-by-step explanation:

The p-value for Factor A is greater than 0.1

What is your conclusion with respect to Factor A?

Factor A is not significant.

The p-value for Factor B is greater than 0.1

What is your conclusion with respect to Factor B?

Factor B is not significant.

The p-value for the interaction of factors A and B is greater than 0.1

What is your conclusion with respect to the interaction of Factors A and B?

The interaction of Factors A and B is not significant.

What is your recommendation to the amusement park?

Since method is not a significant factor, use either loading and unloading method.

4 0
3 years ago
A prepaid phone card has a balance of $22.40 remaining. If calls are $0.035 per minute, which equation represents the number of
Jobisdone [24]

Answer:

0.035m = 22.40

5 0
2 years ago
A group of 80 students in a collage are surveyed.They are asked which of Spanish or French they are studying.71of the students s
pochemuha
It’s C because through a Venn diagram C depicts both French and Spanish.
4 0
3 years ago
How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

  • Mass of copper in x pounds of that 15\% copper alloy: (0.15\, x)\; \rm lb.
  • Mass of copper in 700 pounds of that 30\% copper alloy: 700 \times 0.30 = 210\; \rm lb.

Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

4 0
3 years ago
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