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sdas [7]
1 year ago
10

Given limit of f (x) = 4 as x approaches 0. what is limit of one-fourth left-bracket f (x) right-bracket superscript 4 baseline

as x approaches 0? 0 4 64 128
Mathematics
1 answer:
Otrada [13]1 year ago
4 0

The limit of the given function if \lim_{x \to 0} f(x)=4 is 64

<h3>Limit of a function</h3>

Given the following limit of a function expressed as;

\lim_{x \to 0} f(x)=4

We are to determine the value of the function

\frac{1}{4}  \lim_{x \to 0} [f(x)]^4


This can also be expressed as

\frac{1}{4}  \lim_{x \to 0} [f(x)]^4\\ = \frac{1}{4}(4)^4 \\=1/4\times 256\\=64

Hence the limit of the given function if \lim_{x \to 0} f(x)=4 is 64

Learn more on limit of a function here: brainly.com/question/23935467

#SPJ1

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a blue scarf is 1.7 yards long. A green scarf is 1 whole ad 4/5 yards long. Which scarf is longer ? How much longer ?
Romashka [77]
4/5 as a decimal is 0.8
so 1.7 would be 1.70 and the green one would be 
1.08 so obviously the blue scarf is longer

7 0
3 years ago
Which point on the number line indicates a number that is less than 9.1 and greater than 6.5
Dahasolnce [82]

Answer:


Step-by-step explanation:


8 0
3 years ago
Hailey had 1/5 of a chocolate bar. She decided to
pshichka [43]

Answer:

1/15 each

Step-by-step explanation:

1/5 of chocolate is separated into 3

1/5 divided by 3 = 1/5 x 1/3 = 1/15 of the whole bar

8 0
3 years ago
Find x.<br><br> special 17<br><br> A. 22<br> B. 113√2<br> C. 116√2<br> D. 33
vladimir1956 [14]

The value of x in the triangle is (a) 22

<h3>How to solve for x?</h3>

The complete question is in the attached image.

From the attached image of the triangle, we have:

\sin(45) = \frac{x}{22\sqrt 2}

Evaluate sin(45)

\frac{1}{\sqrt 2} = \frac{x}{22\sqrt 2}

Solve for x

x = \frac{22\sqrt 2}{\sqrt 2}

Divide

x = 22

Hence, the value of x is (a) 22

Read more about special triangles at:

brainly.com/question/654982

#SPJ1

7 0
2 years ago
Multiply. The question is in the picture.
Burka [1]

15a^3b^4c^5----> answer B

you can only multiple like terms so

(5x3)= 15

now just add  

a+a^2= a^3

b + b^3 = b^4

c^5 + 0= c^5

7 0
3 years ago
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