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Bogdan [553]
3 years ago
14

Martin is cleaning the tires of his bicycle. He notices that his bicycle tire has a radius of 8 inches. How much bigger is the a

rea of the tire, than the circumference
Mathematics
1 answer:
algol [13]3 years ago
8 0

Strange question, as normally we would not calculate the "area of the tire." A tire has a cross-sectional area, true, but we don't know the outside radius of the tire when it's mounted on the wheel.

We could certainly calculate the area of a circle with radius 8 inches; it's

A = πr^2, or (here) A = π (8 in)^2 = 64π in^2.

The circumference of the wheel (of radius 8 in) is C = 2π*r, or 16π in.

The numerical difference between 64π and 16π is 48π; this makes no sense because we cannot compare area (in^2) to length (in).

If possible, discuss this situatio with your teacher.



You might be interested in
Please answer this question now
liubo4ka [24]

Answer:

541.67m²

Step-by-step explanation:

Step 1

We find the third angle

Sum of angles in a triangle = 180°

Third angle = Angle V = 180° - (63 + 50)°

= 180° - 113°

Angle V = 67°

Step 2

Find the sides x and v

We find these sides using the sine rule

Sine rule or Rule of Sines =

a/ sin A = b/ Sin B

Hence for triangle VWX

v/ sin V = w/ sin W = x / sin X

We have the following values

Angle X = 50°

Angle W = 63°

Angle V = 67°

We are given side w = 37m

Finding side v

v/ sin V = w/ sin W

v/ sin 67 = 37/sin 63

Cross Multiply

sin 67 × 37 = v × sin 63

v = sin 67 × 37/sin 63

v = 38.22495m

Finding side x

x / sin X= w/ sin W

x/ sin 50 = 37/sin 63

Cross Multiply

sin 50 × 37 = v × sin 63

x = sin 50 × 37/sin 63

x = 31.81082m

To find the area of triangle VWX

We use heron formula

= √s(s - v) (s - w) (s - x)

Where S = v + w + x/ 2

s = (38.22 + 37 + 31.81)/2

s = 53.515

Area of the triangle = √53.515× (53.515 - 38.22) × (53.515 - 37 ) × (53.515 - 31.81)

Area of the triangle = √293402.209

Area of the triangle = 541.66614164081m²

Approximately to the nearest tenth = 541.67m²

5 0
4 years ago
2. Check the boxes for the following sets that are closed under the given
son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Addition

   c) AdditionSum

   d) in this case we have two possibilities

       * If we move to the right the addition

       * If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

        -3 -1 = -4

        -4 -1 = -5

        -7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) 0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}  ...

In this case we can see more clearly the sequence when writing in this way

      0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}

each term is found by adding 1 to the current term,

      \sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}

Therefore the mathematical operation is the addition

c)   ... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...

      The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

  • To move to the right add 1

           -\frac{-10}{2} + 1 = \frac{-10}{2}  -   \frac{2}{2}  = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}

  • To move left subtract 1

         \frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}

         

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Sum

   c) Sum

   d) This case we have two possibilities

  •  If we move to the right the sum
  •  If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0
3 years ago
Marta is solving the equation S = 2πrh + 2πr^2 for h. Which should be the result?
olga_2 [115]

Answer:

h = \frac{S}{2πr} - r


Step-by-step explanation:

The question requires you to make h the subject of the formula.

S = 2πrh + 2πr²

subtract 2πr² on both sides.

S - 2πr² = 2πrh - 2πr² -  2πr²

S - 2πr² = 2πrh

Dividing both sides by  2πr

(S -  2πr²)/2πr =  2πrh/ 2πr

h = \frac{S}{2πr} - r


7 0
3 years ago
Read 2 more answers
The Kansas predicted that in 2018 the population in Centerville would be 17,466 and actuality it was 16,400 what is the percent
sammy [17]

Answer:

6.5%

Step-by-step explanation:

Percentage error formula =

|Estimated value - Real value|/Real value × 100

From the above question,

Estimated value = 17,466

Real value = 16,400

Percentage error = |17,466 - 16,400|/16,400 × 100

= 1066/16,400 × 100

= 0.065 × 100

= 6.5%

Therefore, the percent error = 6.5%

5 0
3 years ago
Read 2 more answers
Solve these inequalities by showing all steps of working <br> b) 5x + 4 &lt; 16 *
Mama L [17]

Step-by-step explanation:

<em><u>5</u></em><em><u>x</u></em><em><u>+</u></em><em><u>4</u></em><em><u><</u></em><em><u>1</u></em><em><u>6</u></em>

<em><u>or</u></em><em><u>,</u></em><em><u>5</u></em><em><u>x</u></em><em><u><</u></em><em><u>1</u></em><em><u>6</u></em><em><u>-4</u></em>

<em><u>or</u></em><em><u>,</u></em><em><u>5</u></em><em><u>x</u></em><em><u><</u></em><em><u>1</u></em><em><u>2</u></em>

<em><u>or</u></em><em><u>,</u></em><em><u>x</u></em><em><u><</u></em><em><u>12</u></em><em><u>÷</u></em><em><u>5</u></em>

<em><u>o</u></em><em><u>r</u></em><em><u>,</u></em><em><u>x</u></em><em><u><</u></em><em><u>1</u></em><em><u>2</u></em><em><u>/</u></em><em><u>5</u></em>

<em><u>or</u></em><em><u>,</u></em><em><u>x</u></em><em><u><</u></em><em><u>2</u></em><em><u>.</u></em><em><u>4</u></em>

<em><u>:</u></em><em><u>.</u></em><em><u>x</u></em><em><u><</u></em><em><u>2</u></em><em><u>.</u></em><em><u>4</u></em>

6 0
3 years ago
Read 2 more answers
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