How do I find the length of AB?

Mathematics

1 answer:

Anit [1.1K]3 years ago

4 0

I assume #3 is 19 because the slope of the line is still the same.
Hope this is right and it helps! I'm not very sure though.

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I’ll give the Brainliest to who answers this question with a reasonable explanation.

topjm [15]

Answer:

$143.8\:\mathrm{ft^2}$

Step-by-step explanation:

The composite figure shown in the picture consists of a semi-circle and a trapezoid. We can even break this trapezoid into a rectangle and two triangles for even simpler calculations. We can find the total area of the figure by simply adding the total area of the shapes we will break the figure into:

Area of semi-circle (half the area of a circle): $\frac{1}{2}\cdot 4.5^2\cdot \pi$

Area of trapezoid (average of bases multiplied by height): $16\cdot 7$

Thus, the total area of the figure is:

$\frac{1}{2}\cdot 4.5^2\cdot \pi+16\cdot 7=143.808625618\approx \boxed{143.8\:\mathrm{ft^2}}$

3 0

2 years ago

Show that there do not exist scalar c1 c2 and c3 c1(-2,9,6)+c2(-3,2,1)+c3(1,7,5)= (0,5,4)

fredd [130]

This is the same as showing the following system of equations doesn't have a solution:

$\begin{cases}-2c_1-3c_2+c_3 = 0 \\ 9c_1 + 2c_2 + 7c_3 = 5 \\ 6c_1 + c_2 + 5c_3 = 4\end{cases}$

or in matrix form,

$\begin{bmatrix}-2&9&6\\-3&2&1\\1&7&5\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\end{bmatrix} = \begin{bmatrix}0\\5\\4\end{bmatrix}$

The quickest way to check if there is a solution is to check whether the coefficient matrix is invertible. If its determinant is 0, then it is not invertible.

And the quickest way to show that the determinant is 0 is by observing that the third row is a linear combination of the first two rows:

(-2, 9, 6) - (-3, 2, 1) = (-2 + 3, 9 - 2, 6 - 1) = (1, 7, 5)

So there are indeed no such scalars c₁, c₂, and c₃.

5 0

2 years ago

Which answer is it? I just learned this today, so I'm confused.

Naily [24]

Answer:

H. $\sqrt{32}$ = 5.7 inches